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Phoenix [80]
4 years ago
6

Why should there be a connection between an element's electron configuration and its location of the periodic table?

Chemistry
1 answer:
Lera25 [3.4K]4 years ago
4 0
The number of energy shells a atom has is denoted by the period. When the energy level increase the period also increases. The number of electrons at the last energy level is denoted by the group.
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(MARK BRAINLEST) PLEASE HELP ASAP: Network covalent solids have an unusual structure. Describe how they are formed, and give two
Amiraneli [1.4K]

Answer:

Covalent network solids are formed by networks or chains of atoms or molecules held together by covalent bonds. Consists of sp3 hybridized carbon atoms, each bonded to four other carbon atoms in a tetrahedral array to create a giant network. Examples of network covalent solids include diamond and graphite (both allotropes of carbon), and the chemical compounds silicon carbide and boron-carbide.

4 0
3 years ago
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Arisa [49]

Answer:

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8 0
3 years ago
The equilibrium expression for kp for the reaction below is __________. n2 (g) o2 (g) 2no (g)
PolarNik [594]
For the reaction;
N2(g) + O2(g) = 2NO(g)

Kp = pNO²/ pN₂pO₂; (No units)
where;
pNO is the partial pressure of NO;
pN₂ is the partial pressure of nitrogen
pO₂ is the partial pressure of Oxygen
The equilibrium constant  Kp is deduced from the balanced chemical equation for a reversible reaction, NOT experimental data as is the case for rate expressions in kinetics. 
Kp changes with temperature considerably changing the position of an equilibrium, and, at a constant temperature, and therefore constant K, the position of an equilibrium can change significantly depending on relative concentrations/pressures of 'reactants' and 'products'.
8 0
3 years ago
In the citric acid cycle, malate is dehydrogenated to oxaloacetate in a highly endergonic reaction with a ΔG’o of +30 kJ mol-1:
Doss [256]

Answer :  The value of K_{eq} of this reaction is, 5.51\times 10^{-6}

At equilibrium, [L-malate] > [oxaloacetate]

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy  = +30 kJ/mol = +30000 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = 25^oC=273+25=298K

K_{eq}  = equilibrium constant  = ?

The given reaction is:

\text{L-malate}+NAD^+\rightleftharpoons \text{oxaloacetate}+NADH+H^+

\Delta G^o=-RT\times \ln K_{eq}

+30000J/mol=-(8.314J/K.mol)\times (298K)\times \ln K_{eq}

K_{eq}=5.51\times 10^{-6}

Therefore, the value of K_{eq} of this reaction is, 5.51\times 10^{-6}

As, the value of K_{eq} < 1 that means the reaction mixture contains reactants.

At equilibrium, [L-malate] > [oxaloacetate]

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4 years ago
if you could take 1 step every second and one step is equal to 3 feel how many miles could you walk in a year of 365 days if you
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If you never stopped you could walk 17918.2 miles
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