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jeka57 [31]
3 years ago
7

hello my BEANS i want to know if u r a girl or a boy so if i call u a boy and u r a girl i am not a bad person i am 13 and i am

good and not a robot pls dont repot me pls
Chemistry
2 answers:
satela [25.4K]3 years ago
6 0
Get off this app and quit wasting time.
finlep [7]3 years ago
4 0

Answer:

okie

Explanation:

imma girl

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What is the molarity of 5.60 mol of sodium carbonate in 1500 ml of solution?
FrozenT [24]

Answer:

3.74 M

Explanation:

We know that molarity is moles divided by liters. The first thing to do here is convert your 1500 mL of solution to L. There's 1,000 mL in 1 L, so you need to divide 1500 by 1000:

1500 ÷ 1000 = 1.50

Now you can plug your values into the equation for molarity:

5.60 mol ÷ 1.50 L = 3.74 M

7 0
3 years ago
Solid silver chloride, AgCI(s), decomposes to its elements when exposed to sunlight Write a balanced equation for this reaction
Mrac [35]

Answer: The coefficient in front of AgCl when the equation is properly balanced is 2.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

Decomposition of silver chloride is represented as:

2AgCl(s)\rightarrow 2Ag(s)+Cl_2(g)

Thus the coefficient in front of AgCl when the equation is properly balanced is 2.

8 0
3 years ago
Am i the only one getting a red text saying my question is mean?
Triss [41]

Answer:

I dont know

Explanation:

8 0
3 years ago
An element has an atomic number of 27. How many protons and electrons are in a neutral atom of the element
Sergeu [11.5K]

Answer:

27 and 32

Explanation:

3 0
2 years ago
Read 2 more answers
I need help with number 8 please help ASAP.
Rzqust [24]

Answer:

33.33% = 33%

Explanation:

MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)

1 mole of MCO3 will produce → 1 mole of CO2

We need to get the number of mole of CO2:

and when we have 0.22 g of CO2, so number of mole = mass / molar mass

Moles = 0.22 g / 44 g/mol = 0.005 mole

Moles of Mg = moles of CO2 = 0.005 mole

Mass of Mg = moles * molar mass

= 0.005 * 84 /mol = 0.42 g

Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100

=33.33 %

8 0
3 years ago
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