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4 years ago

14

When aqueous solutions of potassium carbonate and cobalt(II) sulfate are combined, solid cobalt(II) carbonate and a solution of

potassium sulfate are formed. The net ionic equation for this reaction is:

2 answers:

Lostsunrise [7]4 years ago

6 0

K2CO3 (aq) + CoSO4 (aq) ---> CoCO3 (s) + K2SO4 (aq)

Lesechka [4]4 years ago

4 0

CO3 2- (aq) + Co2+ (aq) ----> CoCO3(s)

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When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu

olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC = C = 0,50 J/gºC

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3 years ago

A swimming pool has the dimensions of 10m, 5m, and 1m. what is the volume?

aliya0001 [1]

It is 50. The answer is 50. 10x5=50 50x1=50

8 0

4 years ago

Read 2 more answers

What is the molarity of a sodium hydroxide solution containing 2 moles of NaOH with a volume of .5L?

Maksim231197 [3]

Answer:

0.4M NaOH

Explanation:

Molarity, M, is an unit of concentration widely used defined as the ratio between moles of solute (In this case, NaOH) and volume of solution in liters.

As the solution contains 2 moles of NaOH-Moles of solute- in 5L of solution, the molarity is:

2 moles NaOH / 5L =

<h3>0.4M NaOH</h3>

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3 years ago

A welding torch requires 602.1 L of ethylene gas at 2.77 atm. What will be the pressure of the gas if ethylene is supplied by a

Katarina [22]

PV=PV
(602.1 L)(2.77atm) = (110.6 L) (X atm)
1667.817=110.6X
15.07971971 atm = X
Rounds to 15.1 (sig figs so much fun)

8 0

2 years ago

Svetllana [295]

Answer:

0.0025moles

Explanation:

Molarity of a solution (M) = number of moles (n) ÷ volume (V)

According to this question, to make 250 mL of a 0.01 M solution of CaCl, the following number of moles is needed:

Volume = 250mL = 250/1000 = 0.250Litres.

Using; molarity = n/V

0.01 = n/0.250

n = 0.0025

n = 2.5 × 10^-3 moles.

5 0

3 years ago