Answer:
Theoretical yield of C8H8BrNO:
In moles
0.000945
In grams
0.204
Explanation:
Theoretical yield of a reaction is defined as the quantity of the product obtained from the complete conversion of a limiting reactant in a chemical reaction. Theoretical yield can be expressed as grams or moles.
Equation of reaction:
C8H9NO + Br2 --> C8H8BrNO + HBr
Since C8H9NO is the limiting reagent, 1 mole of C8H9NO reacted to form 1 mole of C8H8BrNO
Mass of C8H9NO = 129 mg
= 0.129 g.
Molar mass of C8H9NO = 135.17 g/mol.
Number of moles of C8H9NO = mass/molar mass.
= 0.129/135.17
= 0.00095 moles of C8H9NO
Since 1 mole of C8H9NO yielded 1 mole of C8H8BrNO
Therefore, 0.000954 moles of C8H8BrNO
Theoretical yield (in grams) = molar mass * number of moles
= 214.06 * 0.00095
= 0.204 of C8H8BrNO
Answer:
2.75 mol
Explanation:
Given data:
Mass of Nitrogen = 38.5 g
Moles of ammonia produced = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Number of moles of nitrogen:
Number of moles = mass/ molar mass
Number of moles = 38.5 g/ 28 g/mol
Number of moles = 1.375 mol
Now we will compare the moles of ammonia and nitrogen from balance chemical equation.
N₂ : NH₃
1 : 2
1.375 : 2×1.375 = 2.75 mol
Thus 2.75 moles of ammonia are produced from 38.5 g of nitrogen.
