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Sati [7]
4 years ago
14

When aqueous solutions of potassium carbonate and cobalt(II) sulfate are combined, solid cobalt(II) carbonate and a solution of

potassium sulfate are formed. The net ionic equation for this reaction is:
Chemistry
2 answers:
Lostsunrise [7]4 years ago
6 0
K2CO3 (aq) + CoSO4 (aq) ---> CoCO3 (s) + K2SO4 (aq)
Lesechka [4]4 years ago
4 0
CO3 2- (aq) + Co2+ (aq) ----> CoCO3(s)
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Draw the structures of the following compounds from their names: Pentane 3-methyl-hexane 2,4-dimethylpentane
Monica [59]

I am assuming that the compounds given are Pentane, 3-methyl-hexane, and 2, 4-dimethylpentane considering that the compounds were not separated by a comma.

_______________________________________________________

Pentane is in the form of a straight chain alkane. This is important as there are many isomers of Pentane, taking different shapes. By it's name it consists of 5 carbon atoms, and the number of hydrogen atoms should be 12, as the compound is nonpolar.

3-methylhexane is an alkane present in a hexane structure at position 3. There are thus 3 molecules at 3 ends of a hexane structure - H3C, CH3, and CH3

2,4-dimethylpentane is an alkane with respect to the formula [(H3C)2CH]2CH2.

With that information, refer to the three attachments below, for each compound given. They are in order -

8 0
3 years ago
The energy of an electron in a multielectron atom is determined by
Wewaii [24]

Answer:

by principal quantum number (n) and azimuthal quantum number (l)

Explanation:

I used the web to answer so I'm not sure if this is right

5 0
3 years ago
What might be useful for adding solids to a tube
vagabundo [1.1K]
C funnel because the funnel would have a large enough entrance to put a solid through
7 0
4 years ago
I NEED HELP NOW PLEASE<br><br> I KNOW ITS A LOT BUT I REALLY NEED HELP LIKE DESPERATELY
Montano1993 [528]
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3 0
3 years ago
Solution A is a 1.00 L buffer solution that is 1.188 M in acetic acid and 1.188 M in sodium acetate. Acetic acid has a pKa of 4.
Tomtit [17]

Answer:

pH change is -0.07

Explanation:

Using H-H equation for acetic acid:

pH = pKa + log [Acetate salt] / [Acetic acid]

Replacing:

pH = 4.74 + log[1.188M] / [1.188M]

pH = 4.74

The HCl reacts with sodium acetate producing acetic acid, thus:

HCl + CH₃COONa → CH₃COOH + NaCl

That means the final moles of sodium acetate are initial moles - moles of HCl and moles of acetic acid are initial moles + moles of HCl.

As the volume of the buffer is 1.0L, initial moles of both substances are 1.188moles. After reaction, the moles are:

sodium acetate: 1.188mol - 0.1mol = 1.088mol

Acetic acid: 1.188mol + 0.1mol = 1.288mol

Using again H-H equation:

pH = 4.74 + log[1.088M] / [1.288M]

pH = 4.67

pH change is: 4.67 - 4.74 = -0.07

7 0
3 years ago
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