1) Resultant force:
The two forces have same magnitude (4 N) but opposite verse, so their resultant is zero:
2) Couple
The two forces have opposite direction and they are applied at a distance d=0.2 m from the center of the square, so they generate a couple equal to the sum of the torques generated by each force:
The force you are mentioning is called Laurentz Force.
By definition, F = qvB, where q is the charge of the particle, v is the velocity, and B is the field intensity.
Therefore, the particle must be of moving charge.
implement the following boolean function with an 8 to 1 line multiplexer and a single inverter F(A,B,C,D)=(2,3,5,6,8,9,12,14)
Fofino [41]
Examples of such quantities include distance, displacement, speed, velocity, acceleration, force, mass, momentum, energy, work, power, etc. All these quantities can by divided into two categories - vectors and scalars. A vector quantity is a quantity that is fully described by both magnitude and direction.
Answer:
speed wind Vw = 54.04 km / h θ = 87.9º
Explanation:
We have a speed vector composition exercise
In the half hour the airplane has traveled X = 108 km to the west, but is located at coordinated 119 km west and 27 km south
Let's add the vectors in each coordinate axis
X axis (East-West)
-Xvion - Xw = -119
Xw = -Xavion + 119
Xw = 119 -108
Xwi = 1 km
Calculate the speed for time of t = 0.5 h
Vwx = Xw / t
Vwx= 1 /0.5
Vwx = - 2 km / h
Y Axis (North-South)
Y plane - Yi = -27
Y plane = 0
Yw = 27 km
Vwy = 27 /0.5
Vwy = 54 km / h
Let's use the Pythagorean theorem and trigonometry to compose the answer
Vw = √ (Vwx² + Vwy²)
Vw = R 2² + 54²
Vw = 54.04 km / h
tan θ = Vwy / Vwx
tan θ = 54/2 = 27
θ = Tan⁻¹ 1 27
θ = 87.9º
The speed direction is 87. 9th measure In the third quadrant of the X axis in the direction 90-87.9 = 2.1º west from the south