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3 years ago

PLEASE HELP ME ASAP!!!

Physics

2 answers:

juin [17]3 years ago

7 0

The answer is :Plants that have been buried

maks197457 [2]3 years ago

4 0

Answer:

<span>Plants that have been buried</span>

Explanation :

According to the provided graph it is showing that the plant dies and buried before microbes which make them decay , then heat and pressure in Earth's crust for millions of years which can turn into coal,gas, or oil which then is extracted and burnt to create carbon dioxide in which a plant takes it in and the process repeats

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A circular ride has a radius of 32 m If the time of one revolution of a rider is 0.98 s what is the speed of the rider?

11111nata11111 [884]

Given that,

The radius of a circular path, r = 32 m

The time of one revolution of a rider is 0.98 s.

To find,

The speed of the rider.

Solution,

Let v is the speed of the rider. Speed is equal to total distance divided by time taken.

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 32}{0.98}\\\\v=205.16\ m/s$

So, the speed of the rider is 205.16 m/s.

6 0

3 years ago

Calculate the (absolute) pressure at the bottom of a neighborhood swimming pool 30.0 m by 8.0 m whose uniform depth is 2.0 m. Th

Alika [10]

Answer:

Total pressure= 120945[Pa]

Force exerted = 29026800 [N] or 29.02*10^6 [N]

Explanation:

We know that the total pressure is the result of the sum of the atmospheric pressure plus the manometric pressure. The equation is:

$Ptotal=Patm + Pman$

In this problem we know the atmospheric pressure 101.325x10^3 [Pa], therefore we need to find the manometric pressure.

The manometric pressure in the bottom of the swimming pool depends only on the water column of water generated (depth of the swimming pool)

$Pman = density*g*h$

where:

density = density of the water 1000 [kg/m^3]

g= gravity [m/s^2]

h= column of water (meters)

replacing the values:

$Pman= 1000 *9.81* 2 = 19620 [Pa]\\\\$

The total pressure will be:

$Ptotal= 101325+19620 = 120945 [Pa]\\\\$

The force exerte on the bottom is defined by the following expression:

$Pressure=Force/area\\\\Force= Pressure*Area\\\\Area = 30m*8m= 240 m^2Force= 120945*240\\Force= 29026800N or 2958 Ton$

4 0

4 years ago

What is a warming sign that suggest a weight loss plan is a fad diet rather than a healthy weight loss plan?

Serga [27]

Answer:

Warming signs before fad diet includes:

1. When a special type of diet is recommended for weight loss.

2. When quick weight loss is promised instead of advice on the need to exercise, eat healthy foods including fruits and vegetables, and adopt a good feeding behavior.

3. Promises rapid weight loss in a short period of time.

After taking the fad diet the following might be experienced:

1. Constipation.

2. Weakness and fatigue.

3. More accumulation of fats in the body in the long run after a short term normal BMI (Body mass index).

4. Lower metabolic rates over time.

Explanation:

weight loss is a practice adopted by people for various reasons ranging from the desire to stay healthy to, ability to pursue a career that requires a good Body Mass Index. For instance, A BMI (Body mass index) which is equal to a person's weight (kg) / (height(m))^2 of 30 and higher is considered obese.

Fad diet which may give a temporary result of weight loss is not considered totally healthy as it doesn't capture the need to eat a healthy balanced diet instead focuses on more routine consumption of a particular kind of diet.

A healthy weight loss plan captures the need to exercise, reduce body fats while eating healthy. Eating fruits, vegetables are also encouraged.

5 0

3 years ago

Two basketballs of equal mass are rolling toward each other at constant velocities. The first basketball (B1) has a velocity of

slamgirl [31]

$v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)$

<u>Explanation:</u>

Velocity of B₁ = 4.3m/s

Velocity of B₂ = -4.3m/s

For perfectly elastic collision:, momentum is conserved

$m_1v_1 + m_2v_2 = m_1v'_1 + m_2v'_2$

where,

m₁ = mass of Ball 1

m₂ = mass of Ball 2

v₁ = initial velocity of Ball 1

v₂ = initial velocity of ball 2

v'₁ = final velocity of ball 1

v'₂ = final velocity of ball 2

The final velocity of the balls after head on elastic collision would be

$v'_2 = \frac{2m_1}{m_1+m_2} v_1 - \frac{m_1-m_2}{m_1+m_2} v_2\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} v_1 + \frac{2m_2}{m_1+m_2} v_2$

Substituting the velocities in the equation

$v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)$

If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.

5 0

3 years ago

According to the big bang theory, what was the big bang?

sukhopar [10]

I believe the answer is D
Hope this helps :)

6 0

3 years ago