Answer:
74,67 gr/mol
Explanation:
At STP 1 mole of an ideal gas has volume of 22,4 L. Since we know the volume of the gas we can find the number of moles of the gas. (300 mL=0,3 L)
n=0,3L/22,4 L=0,01339 mol
Since we know weight of the gas as 1 g, we can find the molecular weight as;
MW=1 g/0,01339 mol =74,67 gr/mol
Answer: C₂H₄+3 O₂= 2 CO₂+ 2 H₂O
Explanation:
Answer:
10.35
Explanation:
multiply moles by molar mass from periodic table
Your solution in the conical flask will be acidic since you will have gone beyond the amount of acid that should completely neutralise the base completely. thax
According to Avogadro constant 1 mole = 6.02 x 10^23 what about 9.25 x10 ^21
that is 1 mole x ( 9.25 x10 ^21) / (6.02 x10^23) = 0.0154 moles
