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2 years ago

Manganese(IV) oxide is reduced to manganese(II) oxide by hydrogen gas. Include all phases in answer

1 answer:

4 0

MnO2(s)+H2(g)→MnO(s)+H2O(g)

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a compound is decomposed In the laboratory and produces 1.40 g N and 0.20g H what is the empirical formula

Bumek [7]

First, find the number of moles for each element. The molar mass for nitrogen is 14 g/mol and that of hydrogen is 1 g/mol.

1.40 g N / 14 g/mol = 0.1 mol N

0.20 g H / 1 g/mol = 0.2 mol H

Find the mole ratio. Divide both numbers with the much lower value. In this case, it is 0.1 mol N.

For N: 0.1 ÷ 0.1 = 1

For H: 0.2÷0.1 = 2

Thus, the empirical formula is $NH_{2}$ .

7 0

3 years ago

ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a

Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{20\text{ min}}$

$k=3.465\times 10^{-2}\text{ min}^{-1}$

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $3.465\times 10^{-2}\text{ min}^{-1}$

t = time passed by the sample = 80 min

a = initial amount of the reactant = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}$

$a-x=0.100M$

Therefore, the concentration of A after 80 min is, 0.100 M

3 0

2 years ago

A dialysis unit requires 70000 mL of distilled water. How many gallons of water are needed? (1 gal = 4 qt)

Lady bird [3.3K]

Answer: 19.25 gallons

Explanation: 1 ml = 0.0011 quart

Given: 4 quarts = 1 gallon

Thus if 1 ml is equal to 0.0011 quart

70000 ml is equal to = $\frac{0.0011}{1}\times 70000=77quart$

Now if 4 quarts is equal to 1 gallon.

77 quarts is is equal to= $\frac{1}{4}\times 77=19.25gallons$

5 0

3 years ago

Read 2 more answers

An increase in which of the following would increase the boiling point of a liquid?

Doss [256]

Answer:

The boiling point increases with increased pressure up to the critical point, where the gas and liquid properties become identical.

5 0

3 years ago

A 5 grams sample of liquid water evaporates into gaseous water in a closed container, expanding in the process. What is the mass

padilas [110]

We have get the mass of gaseous water after evaporation in a closed container.

The mass of water vapor after evaporation is 5 grams.

In closed container, there is no exchange in mass from system to surrounding, only heat may exchange. The number of moles of water vapour remains unchanged as 5 gram water is heated in closed container.

Due to heating, liquid water gets evaporated and intermolecular distance between water molecules increases in gaseous state than liquid state and intermolecuar force of attraction decreases.

Randomness of molecules increases in gaseous state than liquid state.

5 0

3 years ago