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Pepsi [2]
3 years ago
7

A number cube is rolled and a coin is flipped.

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

30

Step-by-step explanation:

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This is the question ​
AnnZ [28]

Answer:

cool question I love it

3 0
3 years ago
Read 2 more answers
Which properties are used to prove that the expressions 5x+x-2 and 6x-2 are equivalent? 5x+x-2 (5+1)x-2 6x-2
sergeinik [125]

Answer:

Associative and Commutative properties

Step-by-step explanation:

7 0
3 years ago
An electronics store received two shipments of radios. Of the 250 radios in the first shipment, exactly 6% were damaged. In the
nataly862011 [7]

Answer:

Total number of not damaged = 451

C. 451

Step-by-step explanation:

In the first shipment, 6% of the 250 radios where damaged.

Number of damaged= 6/100 * 250

Number of damaged= 6*2.5

Number of damaged= 15 radios.

Number of not damaged= 250-15

Number of not damaged = 235 radios

In the second shipment, 4% of the radios were damaged

Let the number of second shipment= y

0.04 of y where damaged

Total number of radio damaged= 24

15 + 0.04y = 24

0.04y= 24-15

0.04y = 9

Y= 9/0.04

Y= 225

Number of radio in the second shipment= 225

Number of damaged in the second shipment= 0.04*225

Number of damaged in the second shipment= 9

Number of not damaged in the second shipment= 225-9

Number of damaged in the second shipment= 216

Total number of not damaged

= 235+216

= 451

Total number of not damaged= 451

7 0
3 years ago
James wants to promote his band on the internet. Site A offers website hosting for $4.95 per month with a $49.95 startup fee. Si
cupoosta [38]

Answer:

Part 1) see the procedure

Part 2) 4.95x+49.95 < 9.95 x

Part 3) x > 9.99\ months

Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

Step-by-step explanation:

Part 1) Define a variable for the situation.

Let

x ------> the number of months

y ----> the total cost monthly for website hosting

Part 2) Write an inequality that represents the situation.

we know that

Site A

y=4.95x+49.95

Site B

y=9.95x

The inequality that represent this situation is

4.95x+49.95 < 9.95 x

Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B

4.95x+49.95 < 9.95 x

Subtract 4.95x both sides

4.95x+49.95-4.95x < 9.95 x-4.95x

49.95 < 5x

Divide by 5 both sides

49.95/5 < 5x/5

9.99 < x

Rewrite

x > 9.99\ months

Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B.

The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months

4 0
4 years ago
I need help learning how to solve this problem please.
Radda [10]

we have 4 gals, Stephanie, Andrea, Emily and  Becca.

btw the end point should be (-6, -7) and the start point is (8, 6).

so, if we know the distance between those two points, we can just cut it in 4 equal pieces and each gal will be driving a piece.

now, Emily's turn is after Andrea, BUT, we had first Stephenie driving ¼ of the way, then Andrea driving ¼ of the way too, but after ¼+¼, Emily comes on, but ¼+¼ is really 1/2, so when Emily starts, is really half-way through, or the midpoint of that distance.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\stackrel{\textit{Hometown}}{(\stackrel{x_1}{8}~,~\stackrel{y_1}{6})}\qquad&#10;\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}&#10;\qquad&#10;\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-6+8}{2}~~,~~\cfrac{-7+6}{2} \right)\implies \left(\cfrac{2}{2}~,~\cfrac{-1}{2} \right)\implies \stackrel{\textit{Emily starts off}}{\left(1~,-\frac{1}{2} \right)}


Emily's turn ends ¼ of the way later, which will be pretty much half-way in between  (1, -½) and (-6, -7), so is really the midpoint of those two.


\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;(\stackrel{x_1}{1}~,~\stackrel{y_1}{-\frac{1}{2}})\qquad&#10;\stackrel{\textit{San Antonio}}{(\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7})}&#10;\\\\\\&#10;\left( \cfrac{-6+1}{2}~~,~~\cfrac{-7-\frac{1}{2}}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-14-1}{2}~}{2} \right)\implies \left( \cfrac{-5}{2}~,~\cfrac{~\frac{-15}{2}~}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-5}{2}~,~\cfrac{-15}{4} \right)\implies \left( -2\frac{1}{2}~,~-3\frac{3}{4} \right)

8 0
4 years ago
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