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Pepsi [2]
3 years ago
7

A number cube is rolled and a coin is flipped.

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

30

Step-by-step explanation:

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What are the coordinates of the image of point K(1,3) after a reflection over the line y = -1
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Answer:

(1. -3. is the answer. the first option

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Find the derivative of the function using the definition of derivative. g(t) = 7 t g'(t) = State the domain of the function. (En
Vedmedyk [2.9K]

Answer:

R = \{ \forall x \in \mathbf{R}|-\infty <  x < \infty\}

Step-by-step explanation:

The definition of derivative states that:

g'(t) =  \lim_{h \to 0} \frac{g(t+h)-g(t)}{h}

Then:

g'(t) =  \lim_{n \to \infty} \frac{7\cdot (t+h)-7\cdot t}{h}

g'(t) =  \lim_{h \to 0} 7

g'(t) = 7

A constant function is a zero-order polynomial. The domain of any real polynomial is \mathbf{R}. Then, the domain of the function is:

R = \{ \forall x \in \mathbf{R}|-\infty <  x < \infty\}

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3 years ago
How can I solve this equation 6+7x=55
lorasvet [3.4K]

You could solve it with these two steps:

             #1).  Subtract 6 from each side of the equation.
and then
             #2). Divide each side by 7.

If you'll do that, the solution will be right there on the paper in front of you.
It'll begin with "x =", and right after that will be the value of 'x'.


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Write 0.8 in simplest form fraction
grin007 [14]
Listen .8 Is pronounced eight tenths or in fraction eight over ten then simplified to 4 over 5
7 0
4 years ago
The manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .
Misha Larkins [42]

Answer:

0.1507 or 15.07%.

Step-by-step explanation:

We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.

First of all, we will find z-scores for data points using z-score formula.

z=\frac{x-\mu}{\sigma}, where,

z = z-score,

x = Sample score,

\mu = Mean,

\sigma = Standard deviation.

z=\frac{21.97-22}{0.016}

z=\frac{-0.03}{0.016}

z=-0.1875

Let us find z-score of data point 22.03.

z=\frac{22.03-22}{0.016}

z=\frac{0.03}{0.016}

z=0.1875

Using probability formula P(a, we will get:

P(-0.1875

P(-0.1875  

P(-0.1875

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.

6 0
4 years ago
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