Question

If the heat capacity of a ceramic cup is 0.820 j°c-1, how much heat is required to raise the temperature of the cup from 25.0°c to 50.0°c?

Answer 1

Explanation:

Heat is equal to heat capacity multiplied by change in temperature.

Mathematically,        $Q = C \times \Delta T$

where           C = heat capacity

                  $\Delta T$ = change in temperature

Therefore, calculate heat as follows.

                     $Q = C \times \Delta T$

                                = $0.820 j^{o}C \times (50.0 - 25.0)^{o}C$

                                 = 20.5 j

Thus, we can conclude that heat is required to raise the temperature of the cup is 20. 5 joules.

Answer 2

The  heat  required  to raise   the  temperature  of  the  cup  from  25 c   to  50  c  is  calculated  as  follows
Q (heat)  =   c   x  delta  T
c =  specific  heat  capacity  =  0.  820   j/c
  delta T  =  change   in temperature  (  50 c-  25  c  =  25c

=  0.820 j /c  x  25 c  =  20.5  j