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Over [174]
3 years ago
8

If the heat capacity of a ceramic cup is 0.820 j°c-1, how much heat is required to raise the temperature of the cup from 25.0°c

to 50.0°c?
Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Explanation:

Heat is equal to heat capacity multiplied by change in temperature.

Mathematically,        Q = C \times \Delta T

where           C = heat capacity

                  \Delta T = change in temperature

Therefore, calculate heat as follows.

                     Q = C \times \Delta T

                                = 0.820 j^{o}C \times (50.0 - 25.0)^{o}C

                                 = 20.5 j

Thus, we can conclude that heat is required to raise the temperature of the cup is 20. 5 joules.

Aleksandr [31]3 years ago
4 0
The  heat  required  to raise   the  temperature  of  the  cup  from  25 c   to  50  c  is  calculated  as  follows
Q (heat)  =   c   x  delta  T
c =  specific  heat  capacity  =  0.  820   j/c
  delta T  =  change   in temperature  (  50 c-  25  c  =  25c

=  0.820 j /c  x  25 c  =  20.5  j

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