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sashaice [31]
3 years ago
15

If you have 670.0 g of water and wish to make a 2.13 m solution of KBr, how many grams of the solute would you have to add to th

e water that you have?
Chemistry
1 answer:
laila [671]3 years ago
6 0
I believe that for this item, the unit m is for the molality which is equal to mole of solute to kg of solvent. For water that is 670 g, the equivalent in kg is equal to 0.670 kg. Then using the equation,
                          molality = moles solute / kg solvent
and substituting the known values,
                        2.13 = moles solute / 0.670 kg
The amount of solute should be 1.4271 moles. Then, we multiply this value with the molar mass of KBr which is equal to 119.002 g/mol. The answer would be 169.83 g.
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Manganese-58 has a half-life of about 3 seconds. If you have a 90.0 gram sample, how
Rus_ich [418]

Answer:

18.018 seconds.

Explanation:

Given that the half life of Manganese, Mn = 3 seconds. The initial sample mass = 90.0 gram, the final sample mass = 1.40 gram.

The general idea to the question is to look for the time it will take to decay from the initial mass that is 90 gram to 1.40 gram.

Therefore, we will be making use of the formula below;

J(t) = J(o) × (1/2)^t/t(hL).

Where t(hL) is the half life, t is the time taken, J(t)= mass after time,t and J(o) is the initial mass. So, let us slot in the values into the equation above.

1.4 = 90 × (1/2)^ t/3.

1.4/90 = (1/2)^t/3.

t/3 = log(0.5) (1.4/90).

+Please note that the 0.5 of the log is at the subscript).

That is the base 0.5 logarithm of (1.4/90) 0.01556 is 6.0060141295.

t = 3 × 6.0060141295.

t = 18.018 seconds.

4 0
3 years ago
What are the two types of pure substances? Give definitions for each.
BabaBlast [244]
Water and dimond are the 2 pure substances
3 0
3 years ago
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5. Didderent betwen group and period.​
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According to the law of conservation of mass, if an element A has an atomic mass of 2 mass units and element B has an atomic mas
LenaWriter [7]
The law of conservation of mass states that mass is neither created nor destroyed. Since we have 2 g/mol of A and 3 g/mol of B then AB should be equal to the sum of their molar mass that is 

2 g/mol + 3 g/mol = 5 g/mol AB

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A2 = 2 * 2 = 4 g/mol
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therefore A2B3 = 13 g/mol
5 0
3 years ago
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