Can gravity be considered a force?

5. Water, wind, ice, and gravity are important agents of ___ which is a destructive force

Julli [10]

I agree with the statement that the other person has made

6 0

2 years ago

1 Na2CO3(aq) + 1 CaCl2(aq) → 1 CaCO3(s) + 2 NaCl(aq) 4. Use the balanced chemical equation from the last question to solve this

LenKa [72]

<h3>Answer:</h3>

0.6 g NaCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] Na₂CO₃ (aq) + CaCl₂ (aq) → CaCO₃ (s) + 2NaCl (aq)

[Given] 0.5 g Na₂CO₃ reacted with excess CaCl₂

<u>Step 2: Identify Conversions</u>

[RxN] Na₂CO₃ → 2NaCl

Molar Mass of Na - 22.99 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na₂CO₃ - 2(22.99) + 12.01 + 3(16.00) = 105.99 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 0.5 \ g \ Na_2CO_3(\frac{1 \ mol \ Na_2CO_3}{105.99 \ g \ Na_2CO_3})(\frac{2 \ mol \ NaCl}{1 \ mol \ Na_2CO_3})(\frac{58.44 \ g \ NaCl}{1 \ mol \ NaCl})$
Multiply/Divide: $\displaystyle 0.551373 \ g \ NaCl$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

0.551373 g NaCl ≈ 0.6 g NaCl

5 0

3 years ago

The Spirit of America Goodyear blimp has a volume of 2.027×105 ft3.When the blimp is in operation, it is filled with helium gas.

Andru [333]

Answer: 1.027 x 10^6 g= 1027kg
In this question, you are given the volume of the blimp (2.027×10^5 ft^3) and the density of the gas(0.179g/L). To answer this question, you need to convert the volume unit into liter. The calculation would be: 2.027×10^5 ft^3 x 28.3168L/ft3= 57.398 x 10^5L= 5.74x10^6L

Then to find the mass, multiply the volume with the density. The calculation would be: 5.74x10^6L x 0.179g/L= 1.027 x 10^6 g= 1027kg

4 0

3 years ago

Read 2 more answers

To what volume should you dilute 134 mL of an 8.00 M CuCl2 solution so that 48.0 mL of the diluted solution contains 5.89 g CuCl

Tom [10]

Answer:

Explanation:

Number of moles of CuCl2 initially present = volume * molar concentration

= 0.134 * 8

= 1.072 mol.

Molar mass of CuCl2 = 63.5 + (2*35.5)

= 134.5 g/mol

Mass of CuCl2 = molar mass * number of moles

= 134.5 * 1.072

= 144.184 g

Mass of CuCl2 in 48 ml = 5.89 g in 48 ml

Volume = 5.89 * (48/144.184)

= 1.96 ml.

4 0

3 years ago

a metal object has a mass of 9.0g and a volume of 1.5ml. what is the density of the object? density= mass/volume

weeeeeb [17]

The density of the metal object=6.0 $\frac{g}{m l}$

Given:

Volume of the metal object=1.5ml

Mass of the metal object=9.0g

To find:

Density of the metal object

<u>Step by Step Explanation: </u>

Solution:

According to the formula, Density of the metal object can be calculated as

$\rho=\frac{m}{v}$

Where, m=mass of the metal object

$\rho$ =density of the metal object

v=volume of the metal object

We know the values of v=1.5ml and m=9.0g

Substitute these values in the above equation we get

$\rho=\frac{m}{v}$

$\rho$ =9.0/1.5

=6.0 $\frac{g}{m l}$

Result:

Thus the density of the metal object is 6.0 $\frac{g}{m l}$

4 0

3 years ago