Answer: 0.9375 g
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of 
solution = 0.75 M
Volume of solution = 25.0 mL = 0.025 L
Putting values in equation 1, we get:
According to stoichiometry :
2 moles of require = 1 mole of 
Thus 0.01875 moles of will require=
of
Mass of 
Thus 0.9375 g of is required to react with 25.0 ml of 0.75 M HCl
26. B
27. D
28. C
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The mass of CO2 produced by 26g of acetylene is 88g.
Given ,
In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.
The acetylene combustion reaction is given by,
H2O + HCCH + 5/2 O=O 2CO2
Heat of reaction for acetylene combustion = 1259kj/mol
CO2 has a molecular mass of 44g/mol.
2 moles of CO2 have a molecular mass of 88g.
On combustion, 1 mole of acetylene yields 2 moles of CO2.
Thus, 26g of acetylene produces 88g of CO2 when burned.
As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.
Learn more about acetylene here :
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0.600
D) 0.600 is the final concentration of the solution of KCl.
V1 = 50.0 mL.
