Answer:
KE = PE at half the table Height:
Explanation
AT ANY POINT IN THE BOOK'S FALL,
TOTAL E = PE +KE
THE TOTAL E IS CONSTANT
Before the book is pushed off, the total energy is potential
TOT E=PE =MGH
BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC
TOT=KE = MVXV/2
WHEN KE = PE
KE+PE =<u> MGH (STARTING ENERGY SINCE E IS CONSERVED)</u>
<u>OR PE+ PE = MGH</u>
<u>OR MGH' + MGH' =MGH</u>
<u>OR 2H' =</u>H
H' (NEW HEIGHT) =H/2
First one is False. The second is true.
Answer:
Cathode: Ag
Anode: Br₂
Explanation:
In the cathode must occur a reduction, so it's more likely to a metal atom be in the cathode. For the metals given the reduction reactions and the potential of reduction are:
Ag⁺ + e⁻ ⇒ Ag⁰ E° = + 0.80 V
Fe⁺² + 2e⁻ ⇒ Fe⁰ E° = - 0.44 V
Al⁺³ + 3e⁻ ⇒ Al⁰ E° = -1.66 V
As the potential for Ag is the higher, the reduction will occur for it first, so in the cathode will produce Ag.
For the anode an oxidation must occurs, so the reactions for the nonmetals are:
F₂ + 2e⁻ ⇒ 2F⁻ E° = +2.87 V
Cl₂ + 2e⁻ ⇒ 2Cl⁻ E° = +1.36 V
Br₂ + 2e⁻ ⇒ 2Br⁻ E° = +1.07 V
For oxidation, the less the E°, the faster the reaction will occur, so Br₂ will be formed in the anode.
Answer:
Explanation:
R = Rydberg constant = 
= Principal quantum number of an energy level = 2
= Principal quantum number of an energy level for the atomic electron transition = 4
Wavelength is given by the Rydberg formula
The wavelength of the light emitted is .
