The pH of the solution is mathematically given as
PH=7.21
<h3>What would be the pH of the solution?</h3>
Question Parameters:
sodium hydrogen sulfite (NaHSO3) to 50 mL of water.
Generally, the equation for the Chemical Reaction for the acid dissociation is mathematically given as
HSO3- + H2O ---> H3O+ + SO3^2-
Therefore
A-=HA
pH=pKa
Since pKa NaHSO3=7.21
Hence, PH=7.21
For more information on Chemical Reaction
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Answer:
2.453.
Explanation:
<em>∵ pH = - log[H₃O⁺]
</em>
[H₃O⁺] = 0.00352 M.
<em>∴ pH = - log[H₃O⁺] </em>= - log(0.00352) = <em>2.453.</em>
We are given with the equilibrium constant of acid, HF and is asked to calculate the pH of 0.30 M NaF solution. The formula to be followed is
Ka = [H+][F-]/[HF]Ka = 7.2 x 10 -4 = x^2/[0.3-x]x = [H+]= pH = -log (H+) = 1.84
Over time, the particles in the suspension would settle to the bottom when the movement keeping them suspended fades away. This will not happen with a solution.
b
the color of lines
Explanation:
on the atomic spectrum for an atom
