Question

An aqueous solution athas aconcentration of. Calculate theconcentration. Be sure your answer has 1 significant digits.

Answer 1

The question is incomplete, here is the complete question.

An aqueous solution at 25°C has a $OH^-$ concentration of $1.9\times 10^{-8}M$ . Calculate the $H_3O^+$ concentration. Be sure your answer has the correct number of significant digits.

Answer: The hydronium ion concentration of the solution is $5.25\times 10^{-7}$

Explanation:

To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=1.9\times 10^{-8}M$

Putting values in above equation, we get:

$pOH=-\log(1.9\times 10^{-8})$

$pOH=7.72$

To calculate the hydronium ion concentration, we first calculate pH of the solution, which is:

pH + pOH = 14

pH + 7.72 = 14

pH = 14 - 7.72 = 6.28

To calculate the hydronium ion concentration of the solution, we use the equation:

$pH=-\log[H_3O^+]$

We are given:

pH = 6.28

Putting values in above equation, we get:

$6.28=-\log[H_3O^+]$

$[H_3O^+]=5.25\times 10^{-7}$

Hence, the hydronium ion concentration of the solution is $5.25\times 10^{-7}$