How many particles are in 3.4 moles of NaCl?
1 answer:
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Answer: 0.002 M
Explanation:
The balanced chemical equation for ionization of in water is:
According to stoichiometry :
1 mole of ionizes to give =2 mole of
ions
0.001 mole of ionizes to give =
mole of
ions
Thus of a solution of 0.001 M aqueous sulfuric acid is 0.002 M
Answer:
The reaction would shift toward the reactants
When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm
Explanation:
For the reaction:
2NH₃(g) ⇄ N₂(g) + 3H₂(g)
Where K is defined as:
As initial pressures of all 3 gases is 1.0atm, reaction quotient, Q, is:
As Q > K, <em>the reaction will produce more NH₃ until Q = K consuming N₂ and H₂.</em>
Thus, there are true:
<h3>The reaction would shift toward the reactants</h3><h3>When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm</h3><em />