Answer:
0.1388 g
Explanation:
The mass of
obtained on precipitation = 236 mg
1 mg = 0.001 g
Thus, Mass of
= 0.236 g
Molar mass of
= 233.43 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of
= 0.001011 moles
According to the reaction,

Thus, moles of barium = 0.001011 moles
Molar mass of barium = 137.327 g/mol
Thus, Mass = Moles * Molar mass = 0.001011*137.327 g = 0.1388 g
Answer:
A. One unpaired electron
B. 5 unpaired electrons
Explanation:
In A ,Fe is in +3 oxidation state and Electronic configuration- [Ar]3d5
And NO2 is a strong field ligand hence it causes pairing in t2g orbitals and results one unpaired electron in dZX orbital.
In B, also Fe is in +3 oxidation state but F is weak field ligand hence causes no pairing of Electrons hence it results 5 unpaired electrons with electronic configuration t2g^3 eg^2
<h2><u>Answer:</u></h2>
It wasn't an adjustment in the condition of issue on the grounds that the vitality in the can did not change. Additionally, since this was a physical change, the atoms in the can are as yet similar particles. No synthetic bonds were made or broken. You added enough vitality to make a stage change from strong to fluid.
The main changes recorded which don't include framing or breaking substance bonds would bubble and liquefying. Bubbling and liquefying are physical changes as opposed to synthetic changes, so no new items are shaped.