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slega [8]
3 years ago
10

X squared +20 equals 2X

Mathematics
1 answer:
Ivahew [28]3 years ago
5 0

x={1+i√19 , 1-i√19}

solve this by using quadratic formula

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What is the value of s and the length of side BC if ABCD is a rhombus?
laiz [17]

answer

s=45 units

bc=434 units

explanation

Find the value of s

In a Rhombus all sides are congruent so

AB=BC=CD=DA

AB=9s+29

CD=10s−16

equate AB and CD

9s+29=10s−16

Combine like term

10s−9s=29+16

s= 45 units

the value of s is 45 units

Find the value of side AB

AB=9s+29AB=9s+29

substitute the value of s

AB=9*45+29=434 units

Remember that the sides are congruent

AB=BC=CD=DA

therefore

The length of the side BC is 434 units

6 0
3 years ago
HELP NOW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Umnica [9.8K]
I think that it is B because I'm pretty sure it has to be log of 50,000. But I forgot how to get the rest of it but B is the only one with log of 50k.
6 0
3 years ago
Read 2 more answers
Solve the slope for the table.
Nikitich [7]

Answer:

The slope is 0

Step-by-step explanation:

All y-values are equal to 5 meaning the graph is a straight horizontal line. Slope is the rate at which a graph increases or decreases. Seeing as this graph doesn't do so, the slope is 0.

3 0
2 years ago
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The following table shows the length and width of two rectangles:
faltersainse [42]
The perimeter of these can be found by adding length and width and then multiplying by two. 

Rectangle A: (with all of the variables already doubled)
2x + 16 + 2x - 2 
2x + 2x + 16 - 2
4x + 14
So rectangle A's perimeter is 4x + 14.

Rectangle B: (Still with all the variables already doubled)
8x + 10 + 6x - 4
8x + 6x + 10 - 4
14x + 6
So rectangle B's perimeter is 14x + 6

And now to subtract the two.
(7x + 3) - (4x + 14)
14x + 6 - 4x - 14
14x - 4x + 6 - 14
10x - 8

So it would be C.
5 0
3 years ago
For the circle with equation (x-2)^2+(y+3)^2=9, answer each question. a) whats coords of the center? b) what are the radius and
MrRissso [65]

Answer:

<h2>a) center (2, -3)</h2><h2>b) radius r = 3</h2><h2>c) in the attachment</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

(x-2)^2+(y+3)^2=9\\\\(x-2)^2+(y-(-3))^2=3^2

a) center (2, -3)

b) radius r = 3

c) in the attachment

4 0
3 years ago
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