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slega [8]
3 years ago
10

X squared +20 equals 2X

Mathematics
1 answer:
Ivahew [28]3 years ago
5 0

x={1+i√19 , 1-i√19}

solve this by using quadratic formula

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Travis has hired Charlie and Dora to plant flowers. Dora can plant 150 flowers in the same time it takes Charlie to plant 120 fl
slega [8]

Answer:

  72

Step-by-step explanation:

If the rates d and c are flowers per day, we have ...

  150/d = 120/c

  d -c = 18

__

Multiplying the first equation by cd/30, we have ...

  5c = 4d

Multiplying the second equation by 4 gives ...

  4d -4c = 72

Adding these equations together, we get ...

  5c +4d -4c = 4d +72

Simplifying and subtracting 4d leaves ...

  c = 72

Charlie can plant 72 flowers per day.

4 0
2 years ago
Help? Due today please
kiruha [24]

Answer:

PR

Step-by-step explanation:

They're congruent, so corresponding sides of corresponding congruent figures are congruent. A corresponds to P and C corresponds to R, so AC is congruent to PR

6 0
3 years ago
Una empresa exportadora de frutas vende dos variedades de frambuesas: estándar y de lujo. Una caja de freses estándar se vende e
aksik [14]

Answer:

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

Step-by-step explanation:

Representemos el número de cajas como

A = caja estándar de frambuesas

B = caja de lujo de frambuesas

Caja estándar de frambuesas = $ 7 Caja de lujo de frambuesas = 10.

A + B = 135 ......... Ecuación 1

B = 135 - A

7A + 10B = 1100 ........... Ecuación 2

Sustituir

135 - A para B en la ecuación 2

7A + 10 (135 - A) = 1100

7A + 1350 -10A = 1100

7A - 10A = 1100-1350

-3A = - 250

A = 250/3

A = 83.33 cajas

Sustituye 83.33 por A en la ecuación 1

A + B = 135

83,33 + B = 135

B = 135 - 83.33 = 51.67 cajas

Por lo tanto, vendió,

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

6 0
3 years ago
How can u tell if a number is divisible by 3?
vagabundo [1.1K]
To check for divisibility by 3 just check if the sum of all the digits in the number are divisible by 3. If so, the number itself must also be divisible by 3. For example, is 1,529 divisible by 3? Well, the sum of the digits of 1,529 is 1+5+2+9=17. Since 17 is not divisible by 3, we can conclude that 1,529 is also not divisible by 3. How about 1,530? Well, this time the sum is 1+5+3+0=9. Since 9 is divisible by 3, we know that 1,530 is divisible by 3 too.
3 0
3 years ago
Explain how 9 x 4 can help you find 9 x 8
MrMuchimi
You can double the product of 9 and 4 to get to the product of 9 and 8
3 0
3 years ago
Read 2 more answers
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