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Elis [28]
2 years ago
13

Someone please help will mark as brainliest

Chemistry
1 answer:
Karo-lina-s [1.5K]2 years ago
3 0

Answer:

PET works by using a scanning device (a machine with a large hole at its center) to detect photons (subatomic particles) emitted by a radionuclide in the organ or tissue being examined.

Newer technology combines PET and CT into one scanner, known as PET/CT. PET/CT shows particular promise in the diagnosis and treatment of lung cancer, evaluating epilepsy, Alzheimer's disease and coronary artery disease.

Explanation: Most Brainliest Please

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Explain how you would separate a mixture of water, sand, salt and iron filings into its four component parts.
katen-ka-za [31]

You would use the density difference to separate the sand, evaporate the water out (the water vapor will cool back to water if collected). Then use a magnet to get the iron fillings out of the salt.

7 0
3 years ago
Which description best characterizes the motion of particles in a solid?
Masja [62]

Answer:

D. Vibrating around fixed positions

Explanation:

It's right on edge

6 0
2 years ago
Do elements of the halogen family lose one electron to become halide ions
lana66690 [7]
Its on Google..."The group number of a representative element in the periodic table is related to the number of valence electrons it has. ... Elements of the halogen family lose one electron to become halide ions."
5 0
3 years ago
A student places a 100.0°C piece of metal that weighs 85.5 g into 122 mL of 16.0°C water. If the final temperature is 20.2°C, wh
Musya8 [376]

Answer:

The specific heat of the metal is 0.314 J/g°C

Explanation:

Step 1: data given

Temperature of the piece of metal = 100.0 °C

Mass of the metal = 85.5 grams

Volume of water = 122 mL = 122 grams

Temperature of water = 16.0 °C

The final temperature of water = 20.2 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of metal

Heat gained= heat lost

Qgained = - Qlost

Qwater = -Qmetal

Q = m*c* ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒m(metal) = mass of metal = 85.5 grams

⇒c(metal) = the specific heat of metal = TO BE DETERMINED

⇒ΔT(metal) = the change of temperature of metal = T2 - T1 = 20.2 - 100 °C =  -79.8 °C

⇒m(water) = the mass of water = 122 grams

⇒c(water) = the specific heat of water = 4.184 J/g°C

⇒ΔT(water) = the change of temperature of metal = T2 - T1 = 20.2 - 16.0 °C =  4.2 °C

85.5 *c(metal) * -79.8 = -122 * 4.184 * 4.2

c(metal) * (-6822.9) = -2143.9

c(metal) = 0.314 J/g°C

The specific heat of the metal is 0.314 J/g°C

7 0
3 years ago
What would be the vapor pressure at 25.0 °c of a solution of 5.00 g of glucose (c6h12o6) in 100.0 g of ethanol (c2h5oh)?
Crank
Use Raoult's Law:
Psolution = (χsolvent) (P°solvent)

24.90 = (x) (25.756)

x = 0.966765 (this is the solvent mole fraction)

χsolute = 1 - 0.966765 = 0.033235

χsolute = 0.03324 (to four sig figs)
4 0
3 years ago
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