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Katen [24]
3 years ago
11

When playing American​ roulette, the croupier​ (attendant) spins a marble that lands in one of the 38 slots in a revolving turnt

able. The slots are numbered 1 to​ 36, with two additional slots labeled 0 and 00 that are painted green. Consider the numbers 0 and 00 as neither even nor odd. Half the remaining slots are colored red and half are black. Assume a single spin of the roulette wheel is made. Find the probability of the marble landing on a 00 or even slot. The total number of outcomes is and the number of outcomes in the event is
Mathematics
2 answers:
neonofarm [45]3 years ago
7 0

Answer:

Check the explanation

Step-by-step explanation:

1) probability for odd or 00 = (18+1)/38 = 0.5

2) expected value can be calculated as follows :

14 * win probability - 13 * lose probability

=14 * (18/38) - 13*(20/38)

= -0.21

aksik [14]3 years ago
7 0

Answer:

-0.21

Step-by-step explanation:

Firstly the probability for odd or 00 = (18+1)/38 = 0.5

Therefore we can calculate our expected value as follows :

14 * win probability - 13 * lose probability

=14 * (18/38) - 13*(20/38)

Hence our Answer is = -0.21

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