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Snezhnost [94]
3 years ago
9

Sliding friction is _ than the static friction.

Physics
1 answer:
Alona [7]3 years ago
4 0

Answer:

less

Explanation:

Sliding friction is always less than static friction. This is because in sliding friction, the bodies slide with each other and thus the effect of friction is not more. However, it does not happen in the case of static friction.

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The speed of a car is 40m/s after 10 sec suddenly there was a crowd and the driver reduces its speed to 20m/s. What is the decel
aliya0001 [1]

Explanation:

the number 0.4 in P4 from east

4 0
3 years ago
A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity
Viktor [21]

Answer:

-26 m/s.

Explanation:

Hello,

In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:

t=\frac{0m/s-26m/s}{-9.8m/s^2} =2.65s

With which we compute the maximum height:

y=26m/s*2.65s-\frac{1}{2}*9.8m/s^2*(2.65s)^2 \\\\y=34.5m

Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:

v_f=\sqrt{0m/s-(-9.8m/s^2)*2*34.5m}\\ \\v_f=-26m/s

Which is clearly negative since it the projectile is moving downwards the starting point.

Regards.

3 0
4 years ago
PLEASE HELP! 2ND TIME I ASKED THIS!!!
Goshia [24]

The train is moving at 50 m/s and Emma is walking down the aisle with 1 m/s speed in the same direction of train. The relative velocity of Emma with respect to other passengers pf the train would be 1 m/s. This is because, the train is not moving relative to them and only emma is moving at 1 m/s. If a person observes from outside, Emma would have (50 +1) m/s = 51 m/s velocity.

relative velocity when two objects are moving in same direction as oberved from outside observer:

v_{ab}=v_a+v_b

relative velocity when two objects are moving in the opposite directionas oberved from outside observer:

v_{ab}=v_a-v_b

4 0
4 years ago
A process occurs in which a system's potential energy increases while the environment does work on the system.
iogann1982 [59]
Ok, now what do you want to know about it?
4 0
3 years ago
A worker pushed a 25.0 kg block 6.50 m along a level floor at constant speed with a force directed 30.0° below the horizontal. I
Kipish [7]

Answer:

a) 855.41J

b) 855.41J

Explanation:

The force equation is

N - mg - F sinθ = 0

N = mg + F sinθ

The frictonal  force is =

F_x = F cos \theta

U_xN = Fcos\theta

substitute the value of the normal force in the above equation

U_x (mg + Fsin\theta ) = F cos\theta

F = \frac{U_x mg}{cos\theta - U_x sin\theta } \\\\= \frac{0.41 \times 25 \times 9.8 }{cos 30^\circ- 0.41 \times sin30 ^\circ}

= 151.96N

a) work done = F × d

= (151.96) × (6.5) cos30°

= 855.41 J

b) The increase in thermal energy of the block floor system will be equal to the work done by the worker

work done = F × d

= (151.96) × (6.5) cos30°

= 855.41 J

8 0
3 years ago
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