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Snezhnost [94]
2 years ago
9

Sliding friction is _ than the static friction.

Physics
1 answer:
Alona [7]2 years ago
4 0

Answer:

less

Explanation:

Sliding friction is always less than static friction. This is because in sliding friction, the bodies slide with each other and thus the effect of friction is not more. However, it does not happen in the case of static friction.

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If an object accelerates at 10 m/s2 for 4 seconds, how much will its velocity change by?
jek_recluse [69]

Answer:

40 m/s

Explanation:

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Δv=at=10*4=40

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3 years ago
Which of these warnings refers to a chemical property of the material?
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3 years ago
If a steel containing 1.88 wt%C is cooled relatively slowly to room temperature, what is the expected weight fraction of pearlit
Oxana [17]

Answer:

The answer is %pearlite = 0.06%

Explanation:

according to the exercise we have that the percentage is 1.88% C, therefore, the percentage of perlite is equal to:

%pearlite = (B*C)/(A*C) = (2-1.88)/(2-0) = 0.06%

The percentage of cementite is equal to:

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4 0
3 years ago
a concrete cube of side 0.50 m and uniform density 2.0 x 103 kg m–3 is lifted 3.0 m vertically by a crane. what is the change in
AlladinOne [14]

Answer:

Change in potential energy = 7350 Joules

Explanation:

It is given that,

Side of cube, a = 0.5 m

Density of cube, d=2\times 10^3\ kg/m^3

The cube is lifted vertically by a crane to a height of 3 m

We know that, density d=\dfrac{m}{V}

So, m = d × V  (V = volume of cube = a³)

m=2\times 10^3\ kg/m^3\times (0.5\ m)^3

m = 250 kg

We have to find the change in potential energy of the cube. At ground level, the potential energy is equal to 0.

Potential energy at height h is given by :

PE=mgh

PE = 250 kg × 9.8 m/s² ×3 m

PE = 7350 Joules

So, change in potential energy of the cube is 7350 Joules.

5 0
3 years ago
Read 2 more answers
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