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Virty [35]
3 years ago
9

Manuel was jogging with a velocity of 4.113 m/s when he accelerates at 2.091 m/s^2 for 2.991 seconds. How fast is Manuel running

now?
Word Bank:
2.141 m/s^22.141 m/s0.6760 m/s-10.37 m/s10.37 m/s10.37 m/s^25.88 m/s-5.88 m/s0.6760 m/s^2
Physics
2 answers:
Setler [38]3 years ago
7 0

Answer:

k

Explanation:

m

Elden [556K]3 years ago
7 0

Answer:

10.37 m/s

Explanation:

By definition acceleration is computed as follows:

a = (vf - vi)/t

where vf is the final speed, vi the initial speed and t the time elapsed.

Data:

Manuel was jogging with a velocity of vi = 4.113 m/s

accelerates at a = 2.091 m/s²

for t = 2.991 s

Solving for vf in the formula and replacing with data:

vf = a*t + vi

vf = 2.091*2.991 + 4.113

vf = 10.37 m/s

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3 years ago
Which of the following is the BEST explanation for why oceans have two different types of currents?
ivanzaharov [21]

Answer:

sddww

Explanation:

szsswa

7 0
3 years ago
A chair exerts a force of 20 N on a floor and is not moving. What force does
AysviL [449]

The floor exerts 20 N of force on the chair

Explanation:

We can answer this question by using Newton's third law, which states that:

<em>"When an object A exerts a force (called action) on an object B, object B exerts an equal and opposite force (called reaction) on object A"</em>

In this problem, we can identify:

- Object A as the chair

- Object B as the floor

This means that the force of 20 N exerted by the chair on the floor is the action, and so the force exerted by the floor on the chair is the reaction. Newton's third law states that these two forces are equal and opposite: therefore, the force exerted by the floor on the chair is also 20 N, but in the opposite direction.

Learn more about Newton's third law:

brainly.com/question/11411375

#LearnwithBrainly

8 0
3 years ago
What is the electric potential energy of a charge that experiences a force of 3.6 x 10^-4N when it is 9.8 x 10^-5 from the sourc
Levart [38]
The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:
U=qV
The potential is given by the magnitude of the electric field, E, times the distance, d:
V=Ed
So we have
U=qEd (1)
However, the electric field is equal to the electrical force F divided by the charge q:
E= \frac{F}{q}
Therefore (1) becomes
U=Fd
And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
U=Fd=(3.6 \cdot 10^{-4}N)(9.8 \cdot 10^{-5} m)=3.53 \cdot 10^{-8} J
7 0
3 years ago
g Estimate the number of photons emitted by the Sun in a second. The power output from the Sun is 4 × 1026 W and assume that th
vagabundo [1.1K]

Answer:

The value is N  =  1.107 *10^{45 }  \ photons    

Explanation:

From the question we are told that

   The  power output from the sun is  P_o =  4 * 10^{26} \  W

   The average wavelength of each photon is  \lambda  = 550 \  nm  =  550 *10^{-9} \  m

Generally the energy of each photon emitted is mathematically represented as

        E_c =  \frac{h * c  }{ \lambda }

Here  h is the Plank's constant with value  h  =  6.62607015 * 10^{-34} J \cdot s

          c is the speed of light with value  c =  3.0 *10^{8} \  m/s

So

       E_c =  \frac{6.62607015 * 10^{-34}  * 3.0 *10^{8}  }{ 550 *10^{-9} }          

=>   E_c =  3.614 *10^{-19} \  J          

Generally the  number of photons emitted by the Sun in a second is mathematically represented as

         N  =  \frac{P }{E_c}

=>      N  =  \frac{4 * 10^{26} }{3.614 *10^{-19}}

=>      N  =  1.107 *10^{45 }  \ photons    

5 0
2 years ago
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