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Naddik [55]
3 years ago
5

 A cat is being chased by a dog. Both are running in a straight line at constant speeds. The cat has a head start of 3.8 m. The

dog is running with a speed of 8.9 m/s and catches the cat after 6.0 s. How fast did the cat run?
Physics
1 answer:
Mars2501 [29]3 years ago
7 0
In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t, 
= 49.6/6 = 8.267 m/s
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Answer:

h=17357.9m

Explanation:

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To calculate this, you need to use the barometric formula:

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Furthermore, the specific gas constant is defined by:

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P=P_0e^{-\frac{g}{R_{H_2}T}h}

at the surface of the planet (h =0) the pressure is P_0[\tex]. The pressure at the height requested is half of that:[tex]P=\frac{P_0}{2}

applying to the previuos equation:

\frac{P_0}{2} =P_0e^{-\frac{g}{R_{H_2}T}h}

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Which of the following takes place in the combustion chamber of a gas turbine engine?A. A glow plug is used to add enough heat t
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