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Naddik [55]
4 years ago
5

 A cat is being chased by a dog. Both are running in a straight line at constant speeds. The cat has a head start of 3.8 m. The

dog is running with a speed of 8.9 m/s and catches the cat after 6.0 s. How fast did the cat run?
Physics
1 answer:
Mars2501 [29]4 years ago
7 0
In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t, 
= 49.6/6 = 8.267 m/s
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astraxan [27]

Answer:

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Explanation:

Using as convention:

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So the components of the resultant velocity of the jet are

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6 0
3 years ago
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Answer:

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