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Naddik [55]
4 years ago
5

 A cat is being chased by a dog. Both are running in a straight line at constant speeds. The cat has a head start of 3.8 m. The

dog is running with a speed of 8.9 m/s and catches the cat after 6.0 s. How fast did the cat run?
Physics
1 answer:
Mars2501 [29]4 years ago
7 0
In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t, 
= 49.6/6 = 8.267 m/s
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True or False. Recent findings lend strong support to the theory that a black hole lies at the center of the Milky Way and of ma
Genrish500 [490]

Answer:

True

Explanation:

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A radio telescope is an antenna that is capable to perceive the light in the radio part of the electromagnetic spectrum¹.

It is important to notice that in the picture what it can be seen is the effect that the black hole has in the nearby stars.

Key terms:

¹Electromagnetic spectrum: decomposition of light in its different wavelengths (from radio waves to gamma rays).

7 0
3 years ago
La luz roja visible tiene una longitud de onda de 680 nanómetros (6,8 x 10-7 m). La velocidad de la luz es de 3.0 x108 m / s. ¿C
Lina20 [59]

Answer:

Frequency, f=4.41\times 10^{14}\ Hz

Explanation:

Visible red light has a wavelength of 680 nanometers (6.8 x 10⁻⁷ m). The speed of light is 3.0 x 10 ⁸ m / s. What is the frequency of visible red light?

It is given that,

Wavelength of a visible red light is, \lambda=6.8\times 10^{-7}\ m

Speed of light is, c=3\times 10^8\ m/s

We need to find the frequency of visible red light. It can be calculated using below relation.

c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{6.8\times 10^{-7}}\\\\f=4.41\times 10^{14}\ Hz

So, the frequency of visible red light is 4.41\times 10^{14}\ Hz.

3 0
3 years ago
Will give you brainliest pls help
ExtremeBDS [4]

1. All the relevant resistors are in series, so the total (or equivalent) resistance is the sum of the resistances of the resistors: 20 Ω + 80 Ω + 50 Ω = 150 Ω [choice A].

2. The ammeter will read the current flowing through this circuit. We can find the ammeter reading using Ohm's law in terms of the electromotive force provided by the battery: I = ℰ/R = (30 V)(150 Ω) = 0.20 A [choice C].

3. The voltmeter will measure the potential drop across the 50 Ω resistor, i.e., the voltage at that resistor. We know from question 2 that the current flowing through the resistor is 0.20 A. So, from Ohm's law, V = IR = (0.20 A)(50 Ω) = 10. V, which will be the voltmeter reading [choice F].

4. Trick question? If the circuit becomes open, then no current will flow. Moreover, even if the voltmeter were kept as element of the circuit, voltmeters generally have a very high resistance (an ideal voltmeter has infinite resistance), so the current moving through the circuit will be negligible if not nil. In any case, the ammeter reading would be 0 A [choice B].

4 0
3 years ago
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pav-90 [236]

Answer:

the answer is 168.75 J

5 0
3 years ago
What is amplitude?
nydimaria [60]
1. Frequency  is the number of complete waves that pass a point in a second.   2.Wavelength is the distance between two crests or two troughs.                     3.Time period <span> is the time it takes for one complete wave to pass a given point. 4. Amplitude is the height of the wave.   Hence option 4 is correct. </span>
8 0
3 years ago
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