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Neporo4naja [7]
3 years ago
12

In a series circuit, one of the resistors is replaced with a resistor having a lower resistance value. how does this affect the

current in the circuit?
Physics
2 answers:
Assoli18 [71]3 years ago
8 0
Current will increase. 
Hoochie [10]3 years ago
4 0

Answer:

The current in the circuit isn't affected i.e it remains the same

Explanation:

In a series connected circuit, same current flows across the resistors bit different voltage is passed across them. This means that no matter the value of the resistance in a series connected circuit, the current flowing through the resistors will remain the same.

Based on the above conclusion, if one of the resistors is replaced with a resistor having a lower resistance value in a series circuit, the current in the circuit will not be affected.

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Elsie is finishing second grade. If she goes to school 147 day per year and she have 10 years of school left, how many days of s
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Answer:

1,323 days left

Explanation:

147 x 10 = 1,470

1470 - 147 = 1,323

Hopefully this helps you :)

pls mark brainlest ;)

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You push a coin across a table. The coin stops. How does this motion relate to balanced and unbalanced forces?
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Enter an expression in the box to Write the equation of the line perpendicular to y=-3x-1 that passes through the point (3,4).
Dafna11 [192]

Answer: -3x+13

Explanation:

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2 years ago
Which statement correctly describes the organization of cells, tissues, organs, and organ systems within a human body?
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2 years ago
A car's bumper is designed to withstand a 5.04 km/h (1.4-m/s) collision with an immovable object without damage to the body of t
emmasim [6.3K]

Answer:

the magnitude of the average force on the bumper is 3189.8 N

Explanation:

Given the data in the question;

In terms of force and displacement, work done is;

W =F^> × x^>

W = Fxcos\theta    ------- let this be equation 1

where F is force applied, x is displacement and θ is angle between force and displacement.

Now, since the displacement of the bumper and force acting on it is in the same direction,

hence, θ = 0°

we substitute into equation 1

W = Fxcos( 0° )

W = Fx ------- let this be equation 2

Now, using work energy theorem,

total work done on the system is equal to the change in kinetic energy of the system.

W_{net = ΔKE

= \frac{1}{2}mv² -  \frac{1}{2}mu² --------- let this be equation 3

where m is mass of object, v is final velocity, u is initial velocity.

from equation 2 and 3

Fx = \frac{1}{2}mv² -  \frac{1}{2}mu²

we make F, the subject of formula

F = \frac{m}{2x}( v² - u² )

given that mass of car m = 830 kg, x = 0.255 m, v = 0 m/s, and u = 1.4 m/s

so we substitute

F = \frac{830}{(2)(0.255)}( (0)² - (1.4)² )

F = 1627.45098 ( 0 - 1.96 )

F = 1627.45098 ( - 1.96 )

F = -3189.8 N

The negative sign indicates that the direction of the force was in opposite compare to the direction of the velocity of the car.

Therefore, the magnitude of the average force on the bumper is 3189.8 N

6 0
2 years ago
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