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Lyrx [107]
3 years ago
5

When four people with a combined mass of 310 kg sit down in a 2000-kg car, they find that their weight compresses the springs an

additional 0.90 cm. (a) what is the effective force constant of the springs? in N/m (b) The four people get out of the car and bounce it up and down. What is the frequency of the car's vibration?
Physics
1 answer:
luda_lava [24]3 years ago
4 0

Answer:

Explanation:

F=kx

x=F/k

F=2000 kg

x=100 cm=9*10^-3

effective spring constant=k=F/x

k=2000/9*10^-3=2.2*10^-5

now frequency

f=1/2π√k/m

f=1/2*3.14√2.2*10^-5/310

f=1/6.28√7.097*10^-8

f=1/6.28*2.7*10^-4

f=0.16*2.7*10^-4

f=4.32*10^-5

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melamori03 [73]

Answer:

Cl2 + Sb → SbCl3

Cl2 + Sb → SbCl5

Cl2 + Sb → SbCl

Cl2 + Sb → SbCl2

Cl2 + Sb → SbCl3 + SbCl5

Explanation: Hope it will help

7 0
3 years ago
A coin dropped in the lift it takes time 0.5 s to reach the floor when lift is staionary it takes time t when lift is moving up
BARSIC [14]

Answer:

t₁ > t₂

Explanation:

A coin is dropped in a lift. It takes time t₁ to reach the floor when lift is stationary. It takes time t₂ when lift is moving up with constant acceleration. Then t₁ > t₂,  t₁ = t₂,  t₁ >> t₂ ,  t₂ > t₁

Solution:

Newton's law of motion is given by:

s = ut + (1/2)gt²;

where s is the the distance covered, u is initial velocity, g is the acceleration due to gravity and t is the time taken.

u = 0 m/s, t₁ is the time to reach ground when the light is stationary and t₂ is the time to reach ground when the lift is moving with a constant acceleration a.

hence:

When stationary:

s=\frac{1}{2}gt_1^2\\\\t_1^2=\frac{2s}{g}  \\\\When\ moving\ with\ acceleration(a):\\\\s=\frac{1}{2}(g+a)t_2^2\\\\t_2^2=\frac{2s}{g+a}

Hence t₂ < t₁, this means that t₁ > t₂.

4 0
3 years ago
How does the electric force between two charged particles change if one particle's charge is increased by a factor of 2?
Burka [1]
 if one of the charge is doubled, the electric potential energy would be doubled too
8 0
3 years ago
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Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe
JulsSmile [24]

Answer:

(A)  a=2.0.37m/sec^2

(B) s = 146.664 m

Explanation:

We have given car starts from the rest so initial velocity u = 0 m /sec

Final velocity v = 88 km/hr

We know that 1 km = 1000 m

And 1 hour = 3600 sec

So 88km/hr=88\times \frac{1000}{3600}=24.444m/sec

Time is given t = 12 sec

(A) From first equation of motion v = u+at

So 24.444=0+a\times 12

a=2.0.37m/sec^2

So acceleration of the car will be a=2.0.37m/sec^2

(b) From third equation of motion v^2=u^2+2as

So 24.444^2=0^2+2\times 2.037\times s

s = 146.664 m

Distance traveled by the car in this interval will be 146.664 m

6 0
3 years ago
Why does a mountain of uranium not explode as a bomb? ​
djyliett [7]

Answer:

“A mountain of uranium” is an indefinable amount of uranium. If it means uranium ore as found in nature, then the concentration of uranium is orders of magnitude too low for any type of reaction.

Explanation:

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7 0
3 years ago
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