Answer:
6.44 s
Explanation:
Given:
v₀ = 119 m/s
v = 233 m/s
a = 17.7 m/s²
Find: t
v = at + v₀
(233 m/s) = (17.7 m/s²) t + (119 m/s)
t = 6.44 s
Answer:
KE increases and PE decreases.
Explanation:
<u>POTENTIAL ENERGY (PE)</u>:
The potential energy of the rock depends upon the height of the rock, as given by the following formula:
P.E = mgh
Therefore, the potential energy will be highest at the initial point due to the highest height attained by rock. As the rock falls, its height will decrease as a result its <u>potential energy will also decrease</u>.
<u>KINETIC ENERGY (KE)</u>:
The kinetic energy of the rock depends upon the velocity of the rock, as given by the following formula:

Therefore, the kinetic energy will be zero at the initial point due to the zero velocity of the rock. As the rock falls, its velocity will increase as a result its <u>kinetic energy will also increase</u>.
Hence, the correct option will be:
<u>KE increases and PE decreases.</u>
Answer: An exercise, activity, or workout that targets a specific training need Progression - Gradually increasing your skill level and ability over time Overload -Working your body harder than usual to improve how it functions Reversibility - Losing what you have gained by taking time off Tedium - getting bored by doing the same thing
Explanation:
<u>Distance = 12 m</u>
<u>Explanation:</u>
Distance covered by the runner is same as the total path that he has ran. Here, a person starts at 0 position and goes in one direction to position 12 m. Since the initial point is 0 and the final position is 12, the total distance is calculated by adding the 2 points as: 0+12 = 12 m. So the distance covered and the displacement both are same which is 12 meters.
Distance traveled is the full length of the path covered between two points. It is not a vector and the direction is nil and no negative sign. Example : The distance walked by the teacher is 3.0 m ,The distance walked by a passenger is 5.0 m. Also, the distance traveled need not be equal to the magnitude of the displacement which is the distance between the two positions.