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3 years ago

11

What is the device used to detect and measure current?

2 answers:

dybincka [34]3 years ago

6 0

The Ammeter is used to detect and measure current or amperage. Also a more common tool now used is a multimeter that detects and measures voltage, current, and resistance.

Any questions please just ask. Thank you.

morpeh [17]3 years ago

4 0

Answer:galvanometers

Explanation:galvanometers

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Let the resistance of an electrical component remain constant while the potential difference across the two ends of the componen

slamgirl [31]

Answer:

The current through it will also decrease to half of its former value because according to Ohm's law the current flowing through a resistor is directly proportional to the potential difference applied across its ends provided that the temperature and some other necessary conditions remain constant.

This is mathematically represented as follows;

$V=IR.........(1)$

The current is thus given as

$I=\frac{V}{R}..............(2)$

if R is constant and V is reduced to half, then we have the following;

$I=\frac{V/2}{R}$

Simplifying further we obtain

$I=\frac{V}{2R}...........(3)$

Equation (3) shows that the current I is also reduced to half.

8 0

3 years ago

Read 2 more answers

Here is it u can see it

Ymorist [56]

Answer:

The first one is true.

Explanation:

Here it is

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3 years ago

If a car used 260.000 W of power to complete a race in 15 s. how much work did the car do?

marta [7]

Work done by the car is 3900 J

Explanation:

Power and work are related by the equation, Power = Work Done/Time
Power is the rate at which work is done.
Here, the car uses power of 260 W and time taken is 15 s.

Work Done = Power × Time

= 260 × 15 = 3900 J

3 0

3 years ago

A golf club hits a stationary 0.05kg golf ball with and average force of 5.0 x 10^3 newtons accelerating the ball at 44 meters p

maxonik [38]

Answer: The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds

Explanation:

Force applied on the golf ball = $5.0\times 10^3 N$

Mass of the ball = 0.05 kg

Velocity with which ball is accelerating = 44 m/s

Time period over which forece applied = t

$f=ma=\frac{m\times v}{t}$

$t=\frac{0.05 kg\times 44m/s}{5.0\times 10^3 N}=4.4\times 10^{-4} seconds$

$Impulse=(force)\times (time)=f\times t = 5.0\times 10^3\times 4.4\times 10^{-4} seconds=2.2$ Newton seconds

The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds

7 0

3 years ago

I will fan and give 2 medals!!!!!!

Maksim231197 [3]

<span> Corona </span>

<span>I. </span>Rare gaseous envelope

<span>II. </span>Irregular pearly glow

<span>III. </span>Total solar eclipse

<span>IV. </span>Surrounds darkened moon

<span>V. </span>Caused by diffraction

<span> Solar Prominence </span>

<span>I. </span>loop shape

<span>II. </span>large bright gaseous

<span>III. </span>luminous hydrogen gas

<span>IV. </span>rises above chromospheres

<span>V. </span>anchored to surface (sun’s surface)

<span> Solar Flare </span>

<span>I. </span>Intense High-energy

<span>II. </span>Causes electromagnetic disruptions

<span>III. </span>In solar atmosphere

<span>IV. </span>Varies in brightness

<span>V. </span>Emits radiation

<span> Sunspots </span>

<span>I. </span>Surface dark spots

<span>II. </span>Strong magnetic fields

<span>III. </span>Solar magnetic storms

<span>IV. </span> Visible through telescope

<span>V. </span>Cooler than photospheres

I did this in class I got 100%

7 0

3 years ago