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VikaD [51]
3 years ago
5

What a brief summary about why taking Athletics is important.

Physics
1 answer:
svp [43]3 years ago
3 0
Physical education is a component of education that challenges students by providing opportunities to attain the skills and knowledge to be physically active as part of a healthy lifestyle. Demonstrates a variety of physical skills through movement activities.

-from google.
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A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 45 N. How f
kiruha [24]
Work is obtained by multiplying the force and the object's displacement. The force and displacement and force should be in the same direction in order to have work. 
                                      W = F x d
                                     d = W / F
Substituting the known values,
                                     d = 352 J / 45 N = 7.82 m
Thus, the displacement of the student is 7.82 m. 
8 0
4 years ago
What year was the RoboSapien toy robot released?<br> a) 2007<br> b) 2004<br> c) 2020<br> d) dunno
Brilliant_brown [7]

option b )2004........

8 0
3 years ago
To calculate work done on an object, _____. A. multiply the force in the direction of motion by the distance the object moved B.
o-na [289]
I believe your answer would be B, hope it helps

6 0
3 years ago
Read 2 more answers
BEST ANSWER GETS BRAINLIEST!
wel

Answer:

Distance = 16.9 m

Explanation:

We are given;

Power; P = 70 W

Intensity; I = 0.0195 W/m²

Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;

I = Power/Unit area = P/(4πr²)

where;

P is the sound power

r is the distance.

Thus;

Making r the subject, we have;

r² = P/4πI

r = √(P/4πI)

r = √(70/(4π*0.0195))

r = √285.6627

r = 16.9 m

8 0
3 years ago
Se coloca agua en un recipiente de aluminio y se pone a calentar en una estufa que le suministra 230 kj, lo cual hace que la tem
tensa zangetsu [6.8K]

Answer:

32 °C.

Explanation:

Hola.

En este caso, debemos entender que la relación entre el calor y la temperatura viene dada por:

Q=mCp\Delta T

De este modo, dado que estamos estudiando la misma sustancia (agua) con masa constante, la relación calor-temperatura es lineal y directamente proporcional, por tal razón, si se duplica el calor suministrado, la temperatura también será duplicada, de modo que:

\Delta T_{nuevo}=2*16\°C\\\\\Delta T_{nuevo}=32\°C

¡Saludos!

3 0
3 years ago
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