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hjlf
4 years ago
10

Assume an object A with a mass of 66.789 g and a volume of 10.1 mL. what is its density?

Chemistry
1 answer:
docker41 [41]4 years ago
5 0

Answer: 6.61

Explanation:

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the answer for the question is 40 mL

4 0
3 years ago
Answer the following question.
aivan3 [116]

Answer:

B) The north and south Poles

Explanation:

when dealing with magnets they have a negative and Positive charge on their south and north poles. Negative attacks with positive and positive with negative so both poles on each magnet should react to each other

4 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 24.0 g of carbon were burned in the presence of
Novosadov [1.4K]

Answer:

mass of CO2 = 88 g

Explanation:

It is stated in question that 18.7 g of oxygen remained unreacted which means that carbon is limiting reactant. Thus the amount of carbon dioxide produced depend upon the amount of carbon.

Given data:

mass of carbon = 24 g

total mass of oxygen 82.7 g

mass of unreacted oxygen = 18.7 g

mass of carbon dioxide = ?

Solution:

First of we will calculate the moles of carbon.

number of moles of carbon = mass of carbon / atomic weight

number of moles of carbon = 24 g/ 12 g/mol = 2 mol

Chemical equation:

C + O2 → CO2

now we compare the number of moles of carbon and carbon dioxide,

  C   :  CO2

  1    :    1

 2    :    2

Now we will calculate the mass of carbon dioxide from moles.

number of moles of CO2 = mass of CO2 / molar mass of CO2

2 mol × 44 g/mol = mass

mass of CO2 = 88 g

8 0
3 years ago
A solution of sucrose in water is 48.5% sucrose by mass and has a density of 1.118 g/ml. what mass of sucrose, in grams, is cont
telo118 [61]
To determine the mass of sucrose from a given volume of solution, we need to convert the volume into mass by using the density of the solution. We calculate as follows:

mass solution = 3.50 ( 1118 ) = 3913 g

mass of sucrose = 3913 g solution ( .485 g sucrose / g solution ) = 1897.805 g sucrose is present in the solution.
6 0
4 years ago
Read 2 more answers
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