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NemiM [27]
3 years ago
10

Which of the following particles combine to form molecules?

Chemistry
1 answer:
solniwko [45]3 years ago
7 0

Answer: i think its protons and electrons but it also might just be atoms because protons and electrons  make atoms when there are also neutrons

Explanation:

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How do you differentiate between gas and a vapour ?
kolbaska11 [484]
Gas is a substance that will not phase change.

And vapor is a substance above it's boiling point temperature.
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How are ocean waves different from sound waves?
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Answer:

Ocean waves are longitudinal waves, Sound waves are transverse waves. Ocean waves are electromagnetic waves, Sound waves are mechanical waves. A Sound wave of over 20,000 Cycles per Seconds is inaudible to Humans.

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"To determine the amount of heroin in the mixture, you dissolve 1.00 g of the white powdery mixture in water in a 100.0-mL volum
UkoKoshka [18]

Explanation:

Formula to calculate osmotic pressure is as follows.

 Osmotic pressure = concentration × gas constant × temperature( in K)

Temperature = 25^{o} C

                      = (25 + 273) K

                      = 298.15 K  

Osmotic pressure = 531 mm Hg or 0.698 atm     (as 1 mm Hg = 0.00131)

Putting the given values into the above formula as follows.

       0.698 = C \times 0.082 \times 298.15 K


               C = 0.0285

This also means that,

  \frac{\text{moles}}{\text{volume (in L)}} = 0.0285

So,     moles = 0.0285 × volume (in L)

                      = 0.0285 × 0.100

                     = 2.85 \times 10^{-3
}

Now, let us assume that mass of C_{12}H_{23}O_{5}N = x grams

And, mass of C_{12}H{22}O_{11} = (1.00 - x)

So, moles of C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}

                              = \frac{x}{369}

Now, moles of C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}

                   = \frac{x}{369} + \frac{(1.00 - x)}{342}

                  = 2.85 \times 10^{-3}

             = x = 0.346

Therefore, we can conclude that amount of C_{12}H_{23}O_{5}N present is 0.346 g  and amount of C_{12}H_{22}O_{11} present is (1 - 0.346) g = 0.654 g.

4 0
3 years ago
Pls someone help me out
SpyIntel [72]
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2 years ago
Let’s suppose I place a live mouse in closed chambers with a CO2 sensor. In Chamber A, the mouse was given caffeine; therefore t
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Answer:

Explanation:

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