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arlik [135]
3 years ago
5

An experiment using alpha particles to bombard a thin sheet of gold foil indicated that most of the volume of the atoms in the f

oil is taken up by ...
Chemistry
2 answers:
mars1129 [50]3 years ago
6 0
Empty space. We now know that this is the gap between the electrons and nucleus.
antiseptic1488 [7]3 years ago
3 0

The experiment that used alpha particles to bombard a thin sheet of gold foil indicated that most of the volume of the atoms in the foil is taken up by \boxed{{\text{empty space}}}

Further Explanation:

Rutherford’s experiment:

Rutherford's model of atom is the classic model of the atom instead of having many limitations. He designed an experiment that used alpha particles emitted by radioactive elements as objects that can demonstrate the structure of the atom. Rutherford showed his own physical model for the subatomic structure as a result of the experimental observations.

The postulates of Rutherford’s model are as follows:

1. An atom consists of a positive charge in a very small volume. Most of its mass is concentrated in a very small region of the atom and this region was termed as the nucleus of the atom.

2. The nucleus of the atom is surrounded by the negatively charged particles which were called electron. These electrons were supposed to revolve around the atomic nucleus in a circular path at a very high speed. This circular path is called orbit.

3. A very strong electrostatic force of attraction holds together the negatively charged electrons revolving around the nucleus positively charged concentrated in the nucleus.

Limitations of Rutherford’s model:

1. It did not tell anything about the distribution of electrons in various orbits.

2. This model failed to explain Maxwell’s theory of electromagnetic radiation.

3. It was unable to explain the stability of an atom.

Therefore most of the volume of an atom is taken up by empty space in the atom.

Learn more:

1. The major contribution of Antoine Lavoisier to chemistry: brainly.com/question/2500879

2. Example of physical change: brainly.com/question/1119909

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Atomic Structure

Keywords: Rutherford, atom, volume, nucleus, orbit, postulates, limitations, Maxwell, electromagnetic radiations, distribution of electrons, stability of atom.

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When heat is applied to 80 grams of CaCO3, it yields 39 grams of B. Determine the percentage of the yield.
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The question is incomplete, the complete question is:

When heat is applied to 80 grams of CaCO3, it yields 39 grams of CaO Determine the percentage of the yield.

CaCO3→CaO + CO2

<u>Answer:</u> The % yield of the product is 87.05 %

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

We are given:

Given mass of CaCO_3 = 80 g

Molar mass of CaCO_3 = 100 g/mol

Putting values in equation 1, we get:

\text{Moles of }CaCO_3=\frac{80g}{100g/mol}=0.8mol

For the given chemical reaction:

CaCO_3\rightarrow CaO+CO_2

By stoichiometry of the reaction:

If 1 mole of CaCO_3 produces 1 mole of CaO

So, 0.8 moles of CaCO_3 will produce = \frac{1}{1}\times 0.8=0.8mol of CaO

We know, molar mass of CaO = 56 g/mol

Putting values in above equation, we get:

\text{Mass of CaO}=(0.8mol\times 56g/mol)=44.8g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

\% \text{yield}=\frac{39 g}{44.8g}\times 100\\\\\% \text{yield}=87.05\%

Hence, the % yield of the product is 87.05 %

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