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lianna [129]
3 years ago
14

if an atom has 17 electrons and its mass number is 35, calculate the following: - number of protons - number of neutrons -atomic

number
Chemistry
1 answer:
djverab [1.8K]3 years ago
4 0
Electrons, Protons and the Atomic Number is the exact same. So 
Protons - 17
Atomic Number -  17

and the neutrons come by subtracting the protons from the Atomic Mass, which in this case 35. 
35-17 = 18
Neutrons = 18

Protons = 17
Atomic Number = 17
Neutrons = 18

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How many grams of hydrogen gas would be needed to form 8.0 grams of water
steposvetlana [31]
N h2o = mh20/Mh20
= 8.0g/18g/mol
=0.44 mol
therefore n O = 0.44mol
therefore n H2 = 0.88 mol

m H2 = n H2 * M H2
= 0.88 mol * 2 g/mol
=1.76 g
7 0
3 years ago
Suppose we have a 12.2 L sample containing 0.50 mol oxygen gas at a pressure of 1 atm and a temperature of 25 degrees celcius. I
snow_lady [41]

Answer:

c. 8.1 L

Explanation:

Given that:-

Moles of oxygen gas = 0.50 mol

According to the reaction shown below as:-

3O_2\rightarrow 2O_3

3 moles of oxygen gas on reaction gives 2 moles of ozone

Also,

1 mole of oxygen gas on reaction gives 2/3 moles of ozone

So,

0.50 mole of oxygen gas on reaction gives \frac{2}{3}\times 0.50 moles of ozone

Moles of ozone = 0.3333 mol

Pressure = 1 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25.0 + 273.15) K = 298.15 K  

Volume = ?

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 0.3333 mol × 0.0821 L.atm/K.mol × 298.15 K  

⇒V = 8.1 L

6 0
2 years ago
How many moles of calcium (Ca) atoms are there in 77.4 g of Ca?
Vinvika [58]
Lar mass of Ca<span> = 40.08 </span>grams/mole 77.4 g Ca<span> * ( 1 </span>mole Ca<span>/ 40.08 ... n = m / M 1mol </span>Ca<span>weights 40 gmol-1 n = 77,4 / 40 = 1.93 </span>mol<span>.</span>
8 0
3 years ago
Read 2 more answers
The combustion reaction for methane is shown below:
horrorfan [7]

Answer:

P =  14.1 atm    

Explanation:

Given data:

Mass of methane = 64 g

pressure exerted by water vapors = ?

Volume of engine = 24.0 L

Temperature = 515 K

Solution:

Chemical equation:

CH₄ + 2O₂      →      CO₂ + 2H₂O + energy

Number of moles of methane:

Number of moles = mass / molar mass

number of moles = 64 g/ 16 g/mol

Number of moles = 4 mol

Now we will compare the moles of water vapors and methane.

              CH₄          :            H₂O  

                 1            :             2

                 4            :         2/1×4 = 8 mol

Pressure of water vapors:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

P = 8 mol × 0.0821 atm.L/mol.K× 515 K / 24.0 L

P = 338.25 atm.L/ /  24.0 L

P =  14.1 atm      

4 0
2 years ago
A neutral solution has a pH of: <br> a. 1<br> b. 5<br> c. 7<br> d. 14
zavuch27 [327]
The answer is 7 my guy
3 0
3 years ago
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