Iodine-131 is used to

1 answer:

7 0

Iodine 131 is a radioisotope with a very short half-life of 8.02 days, making it highly radioactive. Frequently used in small doses in thyroid cancers therapies, it is also one of the most feared fission products when accidentally released into the environment. Radiotoxicity of iodine 131.

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Please Help!! Qns 1b to 3

Gelneren [198K]

Answer: Ammonium, when heated with aqueous base, will give off NH3 (ammonia) gas, (and depending, water vapor). This will leave the Cr2O3(s). From then on,

it is just adding or subtraction of gases or water vapor. You probably heard “Loss of electrons is Oxidation”, “Gain of Electrons is reduction”. That should help.

Explanation: This isn’t an explanation but an interesting point; Acid-Base and RedOx reactions are useful to the most complex of any Chemistry. Get this down, and Organic Chemistry will be much easier.

7 0

3 years ago

Using the information on page 508, describe a way to make a universal indicator that would tell you the ph of a solution between

vovikov84 [41]

pH stands for the power of hydrogen. pH that ranges form 1-6.9 are acid substances. At pH 1 - 2.9, the substance is highly acidic which will have the color from red to red - orange. At pH 3 - 4, the substance is mildly acidic and the color range is from red - orange to orange. At pH 4.1 – 6.9, the substance is weakly acidic and the color range is from orange to yellow. At pH 7, it is neutral and it is green in color. At pH 7.1-14, it is basic. At pH 7.1 - 10.9, the substance is weakly basic the color range is from green to blue. At pH 11 - 13, the substance is mildly basic and the color range is from blue to purple. At pH 13.1 – 14, the substance is highly basic and the color range is from purple to light purple.

8 0

3 years ago

Heating carvone with aqueous sulfuric acid converts it into carvacrol. The mechanism involves the following steps:

Fittoniya [83]

Answer:

See figure 1

Explanation:

In this question, we have to start with the protonation of the double bond. In carvone we have two double bonds, so, we have to decide first which one would be protonated.

The problem states that the terminal alkene is the one that would is protonated. Therefore, we have to do the protonation in the double bond at the bottom to produce the carbocation number 1. Then, a hydride shift takes place to produce the carbocation number 2. A continuation, an elimination reaction takes place to produce the conjugated diene. Then the diene is protonated at the carbonyl group and with an elimination reaction of an hydrogen in the alpha carbon we can obtain carvacol. 

5 0

2 years ago

Which statements below are an appropriate hypothesis in response to this question? Check all that apply. If a substance changes

Nostrana [21]

Answer:

If a substance undergoes a physical change, then it will retain most of its original properties because no new substance is formed.

If a substance undergoes a chemical change, then it will not retain its original properties because a new substance is formed.

Explanation:

So in shorter words its options 2 and 3

6 0

2 years ago

Read 2 more answers

What is the pH of an acid with a [H+] of 1.0 x 10&-4 M? 1. 4 2. 10 3. 1 4. 7

True [87]

PH scale is from 1 to 14 and indicates how acidic or basic a solution is. To find pH or pOH we need to know the H⁺ ion concentration or OH⁻ concentration.
pH can be calculated using the following equation;
pH = -log[H⁺]
the H⁺ concentration of the given acid is 1.0 x 10⁻⁴ M. substituting this we can find the pH
pH = -log[1x10⁻⁴]
pH = 4
answer is 1) 4

3 0

2 years ago