In Experiment #6 you learned that Zn will dissolve in acidic aqueous solutions as Zn2+, but Cu will not dissolve because Cu is l
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According to law of definite proportion:
In a compound, elements are always arranged in fixed ratio by mass.
Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.
Converting mass into number of moles:
Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,
Similarly, number of moles of oxygen will be:
The ratio of number of moles of carbon and oxygen will be:
Therefore, formula of compound will be CO.
Sample 2:
It has 36.22 g Carbon and 48.00 g Oxygen.
Converting mass into number of moles:
Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,
Similarly, number of moles of oxygen will be:
The ratio of number of moles of carbon and oxygen will be:
The formula of compound will be CO.
Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.