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4 years ago

How do people eat with there noses shut

Engineering

2 answers:

asambeis [7]4 years ago

8 0

People wouldn’t be able to smell

kodGreya [7K]4 years ago

3 0

I don’t know but you wouldn’t be able to smell

You might be interested in

to determine cam ring speed you must use a ___________________,____________________or a________________

saul85 [17]

Answer:

=> The total numbers of cylinders on the engine.

=> Total number of lobes in the cam ring.

=> The direction at which the cam ring rotates.

Explanation:

A cam is a kind of ring and a device that is being used in engines. One or the main purpose of using cams in engines us because it helps in the change or transformation of the rotational movement of the engine to a translational one. Instead of using a cam ring, a cam roller can be used in place.

There are three things that can be used to to determine the speed of cam ring speed and they are given below as;

=> The total numbers of cylinders on the engine.

=> The Total number of lobes in the cam ring.

=> The direction at which the cam ring rotates.

5 0

3 years ago

Two technicians are discussing hand tool use. Technician A says that a 6-point wrench is easier to use in tight places than a 12

Mila [183]

Answer:

<em>Technician B says that a ratchet is used to loosen fasteners that are very tight.</em>

Explanation:

A ratchet is a common wrench device with a fastener component. A ratchet wrench is an essential tool that is used to fasten or loosen nuts and bolts.

8 0

3 years ago

Read 2 more answers

Water flows in a pipeline. At a point in the line where the diameter is 7 in., the velocity is 12 fps and the pressure is 50 psi

PolarNik [594]

Answer:

a) P₂ = 3219.11 lbf / ft² , b) P₂ = 721.91 lbf / ft² , c) P₂ = 5707.31 lbf / ft²

Explanation:

For this exercise we can use the fluid mechanics equations, let's start with the continuity equation, index 1 is for the starting point and index 2 for the end point of the reduction

A₁ v₁ = A₂ v₂

v₂ = v₁ A₁ / A₂

The area of a circle is

A = π r² = π/4 d²

v₂ = v₁ (d₁ / d₂)²

Let's calculate

v₂ = 12 (7/3)²

v₂ = 65 feet / s

Now let's use Bernoulli's equation

P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

P₁ - P₂ = ρ g (y₂ –y₁) + ½ ρ (v₂² - v₁²)

Case 1. The pipe is horizontal, so

y₁ = y₂

P₁ - P₂ = ½ ρ (v₂² –v₁²)

P₂ = P₁ - ½ ρ (v₂² –v₁²)

ρ = 62.43 lbf / ft³

P₁ = 50 psi (144 lbf/ ft² / psi) = 7200 lbf / ft²

P₂ = 7200 - ½ 62.43 / 32 (65² -12²)

P₂ = 7200 - 3980.89

P₂ = 3219.11 lbf / ft²

Case 2 vertical pipe with water flow up

y₂ –y₁ = 40 ft

P₁ - P₂ = ρ g (y₂ –y₁) + ½ rho (v₂² - v₁²)

7200 - P₂ = 62.43 (40) + ½ 62.43 / 32 (65 2 - 12 2) =

P₂ = 7200 - 2497.2 - 3980.89

P₂ = 721.91 lbf / ft²

Case 3. Vertical water pipe flows down

y₂ –y₁ = -40

P₂ = 7200 + 2497.2 - 3980.89

P₂ = 5707.31 lbf / ft²

3 0

3 years ago

Assume a factory releases a continuous flow of wastewater into a local stream, resulting in an in-stream carcinogen concentratio

AlladinOne [14]

Answer:

Calculate the individual residential lifetime cancer risk.

Risk = Potential factor x CDI …… (1)

Calculate the value of C

C = $C_{o} * e^{-kt}$

t = d / v

t = 150 miles / 2 mile per hrs.

t = 75 hrs

t = 75/24

t = 3.13 days

Substitute the obtained value in (2).

C = $C_{o} * e^{-kt}$

C = 0.72 x e^(-0.1*3.13)

C = 0.72 x 0.7313

C = 0.526 mg/L

Substitute the obtained value in (1).

Risk = Potential factor x CDI

Risk = 0.30kg.d/mg x 0.526mg/L x 2L/d x 350day/365days

Risk = 0.3026

8 0

3 years ago

Given the following phasors and the information related to the frequency of that phasor, provide the corresponding time-domain r

Evgesh-ka [11]

Answer:

Explanation:

In Engineering and Physics a Phasor That is a portmanteau of phase vector, is a complex number that represents a sinusoidal function whose Amplitude (A), Angular Frequency (ω), and Initial Phase (θ) are Time-invariant.

For the step by step solution to the question you asked, go through the attached documents.

4 0

3 years ago