Marco is an Italian architect. He has recieved a contract

The uniform beam is supported by two rods AB and CD that have crosssectional areas of 10 mm2 and 15 mm2 , respectively. Determin

ddd [48]

Answer:

w=2.25

Explanation:

It is necessary to determine the maximum w so that the normal stress in the AB and CD rods does not exceed the permitted normal stress.

The surface of the cross-section of the stapes was determined:

A_ab= 10 mm^2

A-cd= 15 mm^2

The maximum load is determined from the condition that the normal stresses is not higher than the permitted normal stress σ_allow.

σ_ab = F_ab/A_ab $\leq$ σ_allow

σ_cd = F_cd/A_cd $\leq$ σ_allow

In the next step we will determine the static size: Picture b).

We apply the conditions of equilibrium:

∑F_x=0

∑F_y=0

∑M=0

∑M_a=0 ==> -w*6*0.5*6*0.75*F_cd*6 =0

==> F_cd = 2*w*k*N

∑F_y=0 ==> F_cd+F_ab - 6*w*0.5 ==>2*w+F_ab -6*w*0.5 =0

==> F_ab = w*k*N

Now we determine the load w

<u>Sector AB: </u>

σ_ab = F_ab/A_ab $\leq$ σ_allow=300 KPa

= w/10*10^-6 $\leq$ σ_allow=300 KPa

w_ab = 3*10^-3 kN/m

<u>Sector CD: </u>

σ_cd = F_cd/A_cd $\leq$ σ_allow=300 KPa

= 2*w/15*10^-6 $\leq$ σ_allow=300 KPa

w_cd = 2.25*10^-3 kN/m

w=min{w_ab;w_cd} ==> w=min{3*10^-3;2.25*10^-3}

==> w=2.25 * 10^-3 kN/m

<u>The solution is: </u>

w=2.25 N/m

note:

find the attached graph

6 0

3 years ago

Para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al

padilas [110]

Answer:

Se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

Explanation:

Dado que para conseguir jugo de naranja concentrada, se parte de un extracto con 7% en peso de sólidos el cual se mete a un evaporador al vacío, y en el evaporador se elimina el agua necesaria para que el jugo salga con una concentración del 60% de peso de sólidos, si se introducen al proceso 1000 kg/h de jugo diluido, para calcular la cantidad de agua evaporada y de jugo concentrado saliente se debe realizar el siguiente cálculo;

1000 x 0.07 = 70

60 = 70

100 = X

100 x 70 / 60 = X

7000 / 60 = X

116.66 = X

Por lo tanto, se obtendrán 116.66 litros de jugo concentrado, y el agua evaporada será por un total de 883.33 litros.

4 0

3 years ago

For a Cu-Ni alloy containing 53 wt.% Ni and 47 wt.% Cu at 1300°C, calculate the wt.% of the alloy that is solid and wt.% of allo

Zina [86]

Answer:

Hello your question is incomplete attached below is the complete question

answer: wt.% of alloy that is solid = 61.5%

wt.% of allot that is liquid = 38.5%

Explanation:

To determine the wt.% of the alloy that is solid

= $\frac{R}{R +S } * 100$

= $\frac{53-45}{58-45} * 100$ = 61.5%

To determine the wt.% of the alloy that is liquid

= $\frac{S}{S+R} * 100\\$

= $\frac{58-53}{58-45} *100$ = 38.5%

attached below is a free hand sketch as well

7 0

3 years ago

A converging - diverging frictionless nozzle is used to accelerate an airstream emanating from a large chamber. The nozzle has a

vodomira [7]

Answer:

a. 617.958kpa

b. 1.351kg/sec

Explanation:

Please see attachment for step by step guide.

5 0

4 years ago

Read 2 more answers

Do not use C++ pointers (this is not a topic of this course).

noname [10]

The program is an illustration of functions in C++

C++ functions are collection of named program statements that are executed when called

<h3>The C++ program</h3>

The program in C++, where comments are used to explain each action is as follows:

#include <iostream>

#include <cmath>

using namespace std;

//This defines the boolean method

bool isoscelesTriangleHeightAndArea(double base, double hypotenuse, double height, double area) {

//This checks for invalid base and height

if(base < 0 || hypotenuse < 0){

return false;

}

//This returns true if base and height are valid

return true;

}

//The main begins here

int main(){

//This initializes the variables

double base, hypotenuse, height, area;

//This gets input for base and hypotenuse

cout<<"Base: "; cin>>base;

cout<<"Hypotenuse: "; cin>>hypotenuse;

//The calls the boolean method

bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

//If success is True

while (success){

//This calculates height

height = sqrt(hypotenuse*hypotenuse - (base/2) * (base/2));

//This calculates area

area = 0.5 * base * height;

//This prints height

cout << "Triangle height is " << height << endl;

//This prints area

cout << "Triangle area is " << area << endl;

//This gets input for base and hypotenuse

cout<<"Base: "; cin>>base;

cout<<"Hypotenuse: "; cin>>hypotenuse;

bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

}

cout << "Invalid Input!" << endl;

}