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forsale [732]
3 years ago
4

An eagle accelerates at 22.35 m/s2 with a force of 120 N. Disregarding other forces acting on the eagle such as gravity and air

resistance, calculate the mass of the eagle. Round the answer to the nearest tenth of a kg. The mass of the eagle is kg.
Physics
2 answers:
andrezito [222]3 years ago
6 0
Recall that force is the result when we multiply the values of an object's mass and acceleration. Mathematically, we have

F = ma

where F is the force (in Newtons, N), m is the mass (in kilograms, kg), and a is the acceleration (in m/s²).

Since we know that the eagle was accelerating at 22.35 m/s² with a force of 120N, we can solve for the eagle's mass as shown below.

m = F/a
m = (120)/(22.35) ≈ 5.4 kg

Hence, the eagle has a mass of approximately 5.4 kg.

Answer: 5.4 kg
IgorC [24]3 years ago
5 0

5.4 kg just did it and it was correct

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A car of mass 1600 kg traveling at 27.0 m/s is at the foot of a hill that rises vertically 135 m after travelling a distance of
Zarrin [17]

Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.  

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

K_1 = K_2 + P + W

then, the work done by the engine is:

W = K_1 - K_2 - P

The formulas for the Kinetic and potential energy are:  

K=\frac{1}{2}mV^2\\P=mgh

where, m is the mass of the car, V the velocity, g the gravity and h is the elevation of the hill.

Using the formulas:

W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh

Replacing the values:

W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

t=\frac{3200m}{20m/s}=160s

the power delivered by the car's engine was:

power=\frac{work}{time}=\frac{1690400J}{160s}=10565W

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