Answer:
Total time= 2.56 s
Explanation:
Given that

So distance = 386242560 m
Velocity of light

We know that
Distance = velocity x time
Now by putting then values

t=1.28 s
So the total time = 2 x 1.28
total time= 2.56 s
Answer:
The answer is Friction.
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Answer:
L = 4.711 *10^{-6} kg m2/s
Explanation:


=4.5*10^-5
angular velocity

= 0.1047 rad/s
the angular momentum,



15/70 =3/14 miles per minute = 0.21 miles a minute. One mile in about 5 minutes. Sarah is shifting, I think (faster than me)
Answer:
The force required to begin to lift the pole from the end 'A' is 240 N
Explanation:
The given parameters for the pole AB are;
The length of the pole, l = 10.0 m
The weight of the pole, W = 600 N ↓
The distance of the center of gravity of the pole from the side 'A' = 4.0 m
Let '
' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive
For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have
× 10.0 m - W × 4.0 m = 0
∴
× 10.0 m = W × 4.0 m = 600 N × 4.0 m
× 10.0 m = 600 N × 4.0 m
∴
= 600 N × 4.0 m/(10.0 m) = 240 N
The force required to begin to lift the pole from the end 'A',
= 240 N.