Answer:
Explanation:
Radius of circular path of coin R = 12.5 x 10⁻²,
coefficient of static friction μs = .33
In order that the coin rotates in circular path , it requires centripetal force which is provided by friction. As speed of rotation increases , force of friction also increases to provide it required centripetal force. When the speed of rotation becomes too high so that frictional force can not compensate the increase in centripetal force then coin will start slipping or it starts moving with respect to turntable.
b ) At this point of time
centripetal force = limiting force of friction
mω² R = μs mg , m is mass of the coin , ω is angular velocity ,
ω² R = μs g
ω² x 12.5 x 10⁻², = .33 x 9.8
ω² = .33 x 9.8 / 12.5 x 10⁻²,
= 25.87
ω = 5.08 rad / s
2π / T = 5.08
T = 2π / 5.08
= 1.23 s .
I think it would be b. Plz mark Brainly ist
Ptolemy's model theorizes that Earth is the center of the universe, and that all planets and the Sun revolve around it. If Venus is between the Earth and the Sun, then the Venus must always be crescent or all dark. <em>Thus, it is impossible to see a full or gibbous face of Venus. </em>Later on, this was disproved by Galileo when he saw through the telescope all phases of Venus. Hence, the heliocentric theory was approved instead.
The number of pascal equivalent to 1 inch of mercury is 3386.53 pascal
From the question given above, we were told that:
29.92 inches of mercury = 1 atm
101325 pascal = 1 atm
Thus,
29.92 inches of mercury = 101325 pascal
- With the above information, we can obtain the number of pascal equivalent to 1 inch of mercury. This can be obtained as follow:
29.92 inches of mercury = 101325 pascal
Therefore,
1 inches of mercury = 101325 / 29.92
<h3>1 inches of mercury = 3386.53 pascal</h3>
Thus, the number of pascal equivalent to 1 inch of mercury is 3386.53 pascal
Learn more: brainly.com/question/12663234
Answer:
a:it speed up
b:it should be positive since final
velocity is larger than initial velocity
c:acceleration is approximately 4.5
m/s^2
Explanation:
initial velocity=u=4.47m/s
Final velocity=v=17.9m/s
Time=t=3 seconds
a:the car speed up since the velocity
increased
b:change in velocity is positive
because final velocity is larger than
initial velocity
17.9-4.47=13.43 m/s
c: acceleration=(v-u)/t
acceleration=(17.9-4.47)/3
acceleration=13.43/3
acceleration=4.5 m/s^2