Answer:
Part A: 2.0 mol.
Part B: 10.8 mol.
Explanation:
- For the balanced reaction:
<em>2N₂O₅(g) → 4NO₂(g) + O₂(g),</em>
It is clear that <em>2 mol of N₂O₅(g)</em> dissociate to <em>4 mol of NO₂(g)</em> and 1 mol O₂(g).
<u><em>Part A 1.0 mol N₂O₅:</em></u>
<u><em>Using cross multiplication:</em></u>
2 mol of N₂O₅(g) produces → 4 mol of NO₂(g), from stichiometry.
1 mol of N₂O₅(g) produces → ??? mol of NO₂(g),
∴ The no. of moles of NO₂ produced = (1 mol)(4 mol)/(2 mol) = 2.0 mol.
<em><u>Part B 5.4 mol N₂O₅:</u></em>
<u><em>Using cross multiplication:</em></u>
2 mol of N₂O₅(g) produces → 4 mol of NO₂(g), from stichiometry.
5.4 mol of N₂O₅(g) produces → ??? mol of NO₂(g),
∴ The no. of moles of NO₂ produced = (5.4 mol)(4 mol)/(2 mol) = 10.8 mol.