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dmitriy555 [2]
3 years ago
6

Four cups of pure water are added to a 20-cup bowl of punch that is 75% juice. What percentage of the new punch is juice?

Chemistry
2 answers:
kolezko [41]3 years ago
8 0

Answer: The percentage of juice present in new punch is 62.5 %.

Explanation:

In 20 cup of punch = 75 % of juice

Cup of juices in 20 cup of punch =

\frac{20\times 75}{100}=15 cups of juice

After addition of 4 cups of water the total volume of punch becomes:

= (15 cups of juice + 5 cups of water)+ (4 cups of water added more) = 24 cups

Percentage of the juice in new punch juice is:

\%=\frac{15}{24}\times 100=62.5\%

The percentage of juice present in new punch is 62.5 %.

postnew [5]3 years ago
7 0
This is an example of a mixture problem. Given that originally, there are 15 cups of juice out of the 20 cups. With the added 4 cups of water, then there will now be 24 cups in total. So the percentage of juice in the new punch would be 15/24, or 62.5%.
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