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kykrilka [37]
2 years ago
8

How many moles are present in 450 grams of sodium phosphide, Na3PNa3P?

Chemistry
1 answer:
BaLLatris [955]2 years ago
5 0

Answer:

4.5moles

Explanation:

Given parameters:

Mass of Na₃P = ?

Unknown:

Number of moles  = ?

Solution;

The number of moles in a given substance can be derived from the expression below;

    Number of moles = \frac{mass}{molar mass}  

Molar mass of  Na₃P   = 3(23) + 31 = 100g/mol

   Number of moles  = \frac{450}{100}   = 4.5moles

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Answer:

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3 years ago
When you put an ice cube into a glass of room temperature water, why does the water get cold?
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The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

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Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

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R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

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T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

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tatyana61 [14]
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