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2 years ago

How many moles are present in 450 grams of sodium phosphide, Na3PNa3P?

Chemistry

1 answer:

BaLLatris [955]2 years ago

5 0

Answer:

4.5moles

Explanation:

Given parameters:

Mass of Na₃P = ?

Unknown:

Number of moles = ?

Solution;

The number of moles in a given substance can be derived from the expression below;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Na₃P = 3(23) + 31 = 100g/mol

Number of moles = $\frac{450}{100}$ = 4.5moles

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Answer:

A tritium is produced.

Explanation:

Combining two additional neutrons to the nucleus of the hydrogen atom makes it a tritium, Hydrogen-3.

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Hydrogen-1 is designated as ₁¹H; a mass number of 1 and atomic number of 1. This particle is actually more like a proton.

Combining both:

₁¹H + 2¹₀n → ³₁H

This is a nuclear reaction and in balancing such reaction equation, mass numbers and atomic numbers must be conserved.

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2 years ago

Starting with acetylene and bromoethane, show how you would use reagents from the table to synthesize 3-hexanone.

ludmilkaskok [199]

The reaction sequence will be

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2 years ago

Some nonliving things that is found in earths environment use an example of how you use each thing

Gnoma [55]

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3 years ago

Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di

pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

$Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)$

Moles of calcium nitrate = $\frac{31.3 g}{164 g/mol}=0.1908 mol$

Moles of ammonium fluoride = $\frac{38.7 g}{37 g/mol}=1.046 mol$

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

$\frac{1}{2}\times 1.046 mol=0.523 mol$ calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

$\frac{2}{1}\times 0.1908 mol=0.3816 mol$ of dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

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2 years ago

Which solution has the same boiling point as 0.25 mol CaCl2 dissolved in 1000 g water?

Rufina [12.5K]

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Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.

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2 years ago