1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alekssandra [29.7K]
2 years ago
14

7th grade science lol help​

Chemistry
1 answer:
Luden [163]2 years ago
8 0

Answer:

C) Organic Weathering

Explanation:

Heat and Cold

And if some people start reporting and making fun of me in this answer don't listen to them.

They are hunting me down.

You might be interested in
How many moles of Al are needed to react completely with 1.8 mol of FeO?
Tju [1.3M]
<span>1.8 × (2/3) = 1.2

brainliest please

</span>
3 0
3 years ago
A sample of a vapor occupies a volume of 500 mL at 65°C. If pressure remains constant, what is the volume of the gas at standard
DedPeter [7]

Answer:

403 mL

Explanation:

First, I will assume that the mole is 1, because you are not specifing this.

Now, with the innitial data, we need to get the pressure:

T = 65+273 = 338 K

V = 500 / 1000 = 0.5 L

Now if:

PV = nRT

Then:

P = nRT/V   and V = nRT/P

Let's calculate the P:

P = 1 * 0.082 * 338 / 0.5 = 55.432 atm

The standard temperature is 0° C or 273 K so, the volume is:

V = 1 * 0.082 * 273 / 55.432

V = 0.40384 L or simply 403.84 mL

8 0
3 years ago
Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
12345 [234]

1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by \Delta T is given by the equation:

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

C=0.385 J/gK is the specific heat capacity of copper

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of copper is

Q=(10)(0.385)(100)=385 J

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

Q=mC\Delta T

where

m is the mass of the block of iron

C is its specific heat capacity of iron

\Delta T is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

C=0.450 J/gK is the specific heat capacity of iron

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of iron is

Q=(10)(0.450)(100)=450 J

6 0
3 years ago
There is a boy i like. i don't think he like me what do i do
SCORPION-xisa [38]

Answer:

tell em

Explanation:

7 0
3 years ago
En el aire que respiramos y en el aire comprimido de los tanques de los buzos se encuentra, además de oxígeno, el gas nitrógeno
marysya [2.9K]

Answer: can someone please translate so i can answer.

Explanation:

sorry

7 0
3 years ago
Other questions:
  • A student has two objects. Object 1 has a mass of 28 g and a volume of 12 cubic
    12·1 answer
  • Activated charcoal is used in gas<br> masks. What physical property is<br> related to this use?
    12·1 answer
  • ilver bromide is used to coat ordinary black-and-white photographic film, while high-speed film uses silver iodide. (a) When 56.
    6·1 answer
  • What hazard classes are the following in?
    7·2 answers
  • What is the amount of heat needed to raise the temperature of 1kg of that substance by 1 degree Celsius?
    7·1 answer
  • 10. Which statement is the most important reason that some people feel that solar energy power can be a pollution-free energy so
    14·1 answer
  • An alpha particle has the same composition as a A) hydrogen nucleus B) deuterium nucleus C) beryllium nucleus D) helium nucleus​
    11·1 answer
  • 6. Calculate the mass of each product when 100.0 g of CuCl react according to the reaction
    5·1 answer
  • 2. C5H10O5 + O2 ---&gt; CO2 + H20
    5·1 answer
  • What are elements made of?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!