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3 years ago

7th grade science lol help

Chemistry

1 answer:

Luden [163]3 years ago

8 0

Answer:

C) Organic Weathering

Explanation:

Heat and Cold

And if some people start reporting and making fun of me in this answer don't listen to them.

They are hunting me down.

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Question 2 of 10

professor190 [17]

Answer:

It's the button with the x, and a blank box above it.

Explanation:

Check the attachments, you'll see what it looks like. It will probably look different on your calculator, but the icon should be the same or similar.

5 0

2 years ago

A ballon is inflated with 2.42L of helium at a temperature of 27.0°C. When put in the freezer, the volume changes to 2.37L and -

natita [175]

Answer:

838 torr

Step-by-step explanation:

To solve this problem, we can use the Combined Gas Laws:

p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₁

p₁V₁ = p₂V₂ × T₁/T₂ Divide each side by V₁

p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?; V₁ = 2.42 L; T₁ = 27.0 °C

p₂ = 754 torr; V₂ = 2.37 L; T₂ = -8.8 °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (27.0 + 273.15) K = 300.15 K

T₂ = (-8.8 + 273.15) K = 264.35 K

(b) Calculate the pressure

p₁ = 754 torr × (2.37 L/2.42) × (300.15/264.35)

p₁ = 754 torr × 0.979 × 1.135

p₁ = 838 torr

5 0

4 years ago

657 g of 2-chloro-2,4-dimethylpentane (g/mol = 134.65) is generated from a reaction between 2,4-dimethyl-2-pentanol (g/mol = 116

jasenka [17]

For a 100% yield 761.31 g of 2-chloro-2,4-dimethylpentane will be produced.

5 0

3 years ago

Please help, thank you! :D

Nezavi [6.7K]

25.13(5512)
4568%of the time is 56789
5678
4333

5 0

3 years ago

Determine the theoretical yield of HCl if 60.0 g of BC13 and 37.5 g of H20 are reacted according to the following balanced react

Pie

Answer : The theoretical yield of HCl is, 56.1735 grams

Explanation : Given,

Mass of $BCl_3$ = 60 g

Mass of $H_2O$ = 37.5 g

Molar mass of $BCl_3$ = 117 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $HCl$ = 36.5 g/mole

First we have to calculate the moles of $BCl_3$ and $H_2O$ .

$\text{Moles of }BCl_3=\frac{\text{Mass of }BCl_3}{\text{Molar mass of }BCl_3}=\frac{60g}{117g/mole}=0.513moles$

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{37.5g}{18g/mole}=2.083moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$BCl_3(g)+3H_2O(l)\rightarrow H_3BO_3(s)+3HCl(g)$

From the balanced reaction we conclude that

As, 1 mole of $BCl_3$ react with 3 mole of $H_2O$

So, 0.513 moles of $BCl_3$ react with $3\times 0.513=1.539$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $BCl_3$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $HCl$ .

As, 1 mole of $BCl_3$ react to give 3 moles of $HCl$

So, 0.513 moles of $BCl_3$ react to give $3\times 0.513=1.539$ moles of $HCl$

Now we have to calculate the mass of $HCl$ .

$\text{Mass of }HCl=\text{Moles of }HCl\times \text{Molar mass of }HCl$

$\text{Mass of }HCl=(1.539mole)\times (36.5g/mole)=56.1735g$

Therefore, the theoretical yield of HCl is, 56.1735 grams

7 0

3 years ago

7th grade science lol help​

7th grade science lol help