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Kazeer [188]
2 years ago
6

2. Use the following combined gas law formula and compute the volume that the butane sample will occupy at STP. (HINT: Convert b

oth temperatures to Kelvin.) Pbutane x Voriginal/Troom = Pstandard x Vfinal/Tstandard
DATA TABLE
Initial mass of butane lighter-21.8 g
Final mass of butane lighter-21.6 g
Volume of butane released-50 mL
Temperature of water-22 oC
Atmospheric pressure-763mm Hg
Chemistry
2 answers:
enyata [817]2 years ago
7 0

Answer: STP stands for standard temperature and pressure and refers to conditions of 273K (0 degree centigrade) at 760mmHg.

Explanation: Temperature, T1= 273 + 22= 295K; Pressure, P1= 763mmHg; Volume, V1= 50mL; T2= 273K; P2= 760mmHg; V2= ?

P1*V1/ T1 = P2*V2/ T2

V2= P1*V1*T2/P2*T1

V2= 763*50*273/760*295

∴ V2= 10414950/224200 = 46.45mL

MrRissso [65]2 years ago
3 0
When we put Boyle's law<span>, Charles' </span>law<span>, and Gay-Lussac's </span>law<span> together, we come up with the </span>combined gas law<span>, which shows that: Pressure is inversely proportional to volume, or higher volume equals lower pressure. It is expressed as:

</span><span>Pbutane x Voriginal/Troom = Pstandard x Vfinal/Tstandard 

It seems that the given values is not complete the pressure of butane is not given and also we cannot calculate for it since there is no more than two data about the water.</span>
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