First we have to refer
to the reaction between the acid and the base: <span>
H2SO4 + 2 NaHCO3 ---> 2 H2O + 2 CO2 + Na2SO4
From this balanced equation we can see that for every 1 mol
of acid (H2SO4), we need 2 mol of base (NaHCO3) to neutralize it. Given 28 ml
of 5.8 M acid, we need to find out how many mols of acid that is:
<span>28mL * (1L/1000mL) * 5.8 mol/L = 0.1624 mol H2SO4</span></span>
<span>
Since we need 2 mol of base per mol of acid, we need:</span>
<span> 2*0.1624 mol = 0.3248 mol NaHCO3 </span><span>
MolarMass of NaHCO3 is 84.01 g/mol
<span>0.3248 mol*(84.01g/mol) = 27.29 g NaHCO3</span></span>
The answe is 56 setup the word primooo
The molarity of the diluted solution is 0.2706 M.
Given,
M₁ = 1.1 M
V₁ = 123 mL
V₂ = 500.0 mL
The dilution law formula is M₁V₁ = M₂V₂
1.1*123=M₂*500
M₂=0.2706 M
<h3 /><h3>Molarity </h3>
Molarity, a concentration unit used in chemistry, is determined by dividing the number of moles of a solute by the number of liters of solution. The phrase "molar concentration" (also known as "molarity," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.
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Answer:
I need the actual answer choices to answer... BUT A pure element or compound contains only one substance, with no other substances mixed in. An example of a “pure compound” is salt.
