Answer:
2-methyl-2-butanol and 2-ethoxy-2-methylbutane
Explanation:
When the elimination occurs, a good leaving group must leave the compound and will be replaced. A good leaving group is a nucleophile, which intends to bond with compounds with positive charges. In this case, the bromine and iodine ions are nucleophiles that will leave the compounds.
In the mixture ethanol and water, two compounds must replace the leaving groups, which are strong nucleophiles: OH⁻ and ⁻OCH₂CH₃ (O is a strong nucleophile, and after the bonding, H⁺ will be lost in the ethanol molecule).
So, the two possible products are 2-methyl-2-butanol and 2-ethoxy-2-methylbutane, as shown below.
Answer:
There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout. The most common type of homogenous mixture is a solution, which can be a solid, liquid, or gas.
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Answer:
[Kr] 4d² 5s²
Explanation:
In group 2 and period 2 is the element Zirconium. Here's an example A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium, we make the substitution of [Ne] for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes [Ne]3s1.
If the resources run out and there is no way to get them all motors will have to be switched to solar or some other source.
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Answer:
55,124.729438282
Explanation:
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