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3 years ago

6

A wagon wheel consists of 8 spokes of uniform diameter, each of mass ms and length L cm. The outer ring has a mass mring. What i

s the moment of inertia of the wheel

1 answer:

just olya [345]3 years ago

6 0

Answer:

The moment of inertial of the wheel, $I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2$

Explanation:

Given;

8 spokes of uniform diameter

mass of each spoke, = $M_s$

length of each spoke, = L

mass of outer ring, = $M_r$

The moment of inertial of the wheel will be calculated as;

$I = 8I_{spoke} + I_{ring}$

where;

$I_{spoke$ is the moment of inertia of each spoke

$I_{ring$ is the moment of inertia of the rim

Moment of inertia of each spoke $=\frac{1}{3}M_sL^2$

Moment of inertial of the wheel

$I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2$

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A 645-turn coil with a 20.250 m 2 area is spun in Earth’s 5.00×10 −5 T magnetic field, producing a 1.25-V maximum emf. A

Dmitriy789 [7]

Answer:

$\omega = 1.914\ rad/s$

Explanation:

Given,

Number of turns, N = 645 N

Area, A = 20.25 m²

Earth Magnetic field, B = 5 x 10⁻⁵ T

Maximum Emf = 1.25 V.

Angular velocity, ω = ?

Using Induced Emf formula

$\varepsilon = NAB\omega$

$\omega= \dfrac{\varepsilon}{NAB}$

$\omega= \dfrac{1.25}{645\times 20.25\times 5\times 10^{-5}}$

$\omega = 1.914\ rad/s$

Angular velocity of the coil = $\omega = 1.914\ rad/s$

5 0

4 years ago

the density of maple wood is about 755.kg/m. What is the mass of a solid piece of maple that has a volume 640.cm?

jenyasd209 [6]

I believe that the correct given values are:

density = 755 kg/m^3

volume = 640 cm^3

First let us convert volume to m^3 units.

volume = 640 cm^3 * (1 m / 100 cm)^3 = 6.4 x 10^-4 m^3

so the mass is:

mass = 755 kg/m^3 * (6.4 x 10^-4 m^3)

<span>mass = 0.4832 kg = 483.2 g</span>

4 0

3 years ago

What are the element names for the following symbols? Ni,He, Pb

vladimir1956 [14]

Ni is Nickel.
He is Helium.
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7 0

3 years ago

Read 2 more answers

A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex

Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

$v_i = v_o$

now at the end of 80 s let the speed is

$v_f = v_1$

after another 120 s let the speed will be

$v_f' = v_2$

now we know that

$d = \frac{v_i + v_f}{2} (t)$

$d = \frac{v_o + v_1}{2}(80)$

$1000 = 40(v_o + v_1)$

also we know that

$v_1 - v_o = a(80)$

also we have

$1000 = \frac{v_1 + v_2}{2}(120)$

$1000 = 60(v_1 + v_2)$

now we can say

$(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}$

also we know

$v_2 - v_o = a(120 + 80)$

$-8.33 = 200 a$

$a = -0.042 m/s^2$

Part b)

now we have

$v_1 + v_o = 25$

$v_1 - v_o = (-0.042)(80)$

$v_1 = 10.83 m/s$

so the starting velocity of the trip is

$v_o = 25 - 10.83 = 14.17 m/s$

now speed after t = 200 s is given as

$v_2 = v_o + at$

$v_2 = 14.17 - (0.042)(200)$

$v_2 = 5.77 m/s$

5 0

3 years ago

You are holding a shopping basket at the grocery store with two 0.60 kg cartons of cereal at one end of the basket. The basket i

ludmilkaskok [199]

Answer:

The gallon of milk is placed at a distance of 0.641 meters.

Explanation:

We have,

Mass of two 0.6 kg cartons of cereal is 1.2 kg

Length of the basket, l = 0.77 m

Center of the basket is 0.385 m

Mass of the half gallon of milk is 1.8 kg

Total weight in the basket is 1.2 + 1.8 = 3 kg

We need to find the position of the gallon of milk so that the center of mass (COM) of your groceries is at the center of the basket.

So,

(3 × 0.385) = (1.2 × 0) + (1.8 × x)

1.155 = 1.8 x

x = 0.641 meters

So, the gallon of milk is placed at a distance of 0.641 meters.

5 0

4 years ago