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NikAS [45]
3 years ago
6

A wagon wheel consists of 8 spokes of uniform diameter, each of mass ms and length L cm. The outer ring has a mass mring. What i

s the moment of inertia of the wheel
Physics
1 answer:
just olya [345]3 years ago
6 0

Answer:

The moment of inertial of the wheel,  I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2

Explanation:

Given;

8 spokes of uniform diameter

mass of each spoke, = M_s

length of each spoke, = L

mass of outer ring, = M_r

The moment of inertial of the wheel will be calculated as;

I = 8I_{spoke} + I_{ring}

where;

I_{spoke is the moment of inertia of each spoke

I_{ring is the moment of inertia of the rim

Moment of inertia of each spoke =\frac{1}{3}M_sL^2

Moment of inertial of the wheel

I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2

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