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statuscvo [17]
3 years ago
11

A 2.0kg solid disk rolls without slipping on a horizontal surface so that its center proceeds to the right with a speed of 5.0 m

/s. What is the instantaneous speed of the point of the disk that makes contact with the surface?
Physics
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

Instantaneous speed of contact point will be ZERO

Explanation:

As we know that disc is rolling without slipping on horizontal surface

So here the speed of center of the disc is given as

v = 5 m/s

now at the contact point the tangential speed will be in reverse direction

v_t = R\omega

now we know that net contact speed with respect to its lower surface must be zero

v_{net} = v - v_t = 0

so net velocity of contact point with respect to its lower surface must be ZERO here

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A container has a 5m^3 volume capacity and weights 1500 N when empty and 47,000 N when filled with a liquid. What is the mass de
Helen [10]

Answer:

927.62 kg/m³ and 0.9275.

Explanation:

Density: This can be defined as the ratio of the mass of a body and its volume.

The S.I unit of density is kg/m³.

Mathematically, Density can be expressed as

D = m/v......................... Equation 1

Where D = density of the body, m = mass of the body,v = volume of the body

Also,

m = W/g.................... Equation 2

Where W = weight of the body, g = acceleration due to gravity.

Given: W = 47000 - 1500 = 45500 N, g = 9.81 m/s²

Substitute into equation 2,

m = 45500/9.81

m = 4638.12 kg.

Also given: v = 5 m³

Substitute into equation 1,

D = 4638.12/5

D = 927.62 kg/m³

Hence the mass density of the liquid = 927.62 kg/m³

Specific gravity: This is the ratio of the density of a body to the density pf water.

R.d  = D/D'................................ Equation 3

Where R.d = specific gravity, D = density of the liquid, D' = density of water.

Given: D = 927.62 kg/m³, D' = 1000 kg/m³

Substitute into equation 3

R.d = 927.52/1000

R.d = 0.9275.

Hence the specific gravity of the liquid = 0.9275.

6 0
3 years ago
An inductor with L = 9.80 mH is connected across an ac source that has voltage amplitude 41.5 V . What value for the frequency o
sashaice [31]

Answer:

149.8Hz

Explanation:

V=I.(XL).........{1}

where (XL) is inductive reactance

(XL) =2πfL......... {2}

V= 41.5, l= 4.5, L= 9.8* 10^-³

take π to be 3.14

(XL) = V/I

= 41.5/4.5

= 9.22

f = (XL) /2πL

= 9.22* 10^³/6.28* 9.8

=149.8

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4 years ago
Hallar la energía mecánica de un pendulo , en un punto de su oscilación donde la energía cinética es 0,39 J y en ese mismo punto
iris [78.8K]

Answer:

E = 0,39 + 0,59 = 0,98 J

Explanation:

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3 years ago
todos los cuerpos pueden estar sobre la tierra por la fuerza de gravedad .cuando nos caemos ,saltamos y realizamos otras activid
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What is the difference between balanced forces and action-reaction forces​
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