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Ivenika [448]
3 years ago
10

What is the difference between balanced forces and action-reaction forces​

Physics
1 answer:
Free_Kalibri [48]3 years ago
6 0

when a number of force acting on a body doesn't changes its motion it is called balanced force

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Just about everyone at one time or another has been burned by hot water or steam. This problem compares the heat input to your s
tatyana61 [14]

Answer:

Q_T=63313.5\ J

Explanation:

Given:

  • temperature of skin, T_s=34^{\circ}C
  • initial temperature of steam vapour, T_v=100^{\circ}C
  • latent heat of steam, L=2256\ J.g^{-1}
  • mass of steam, m=25\ g
  • specific heat of water, c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}
  • final temperature, T_f=34^{\circ}C

<em>Assuming that no heat is lost in the surrounding.</em>

<u>We know:</u>

Q=m.c.\Delta T

<u>Now the total heat given by the steam to form water at the given conditions:</u>

Q_T=Q_{Lv}+Q_w ..............................(1)

where:

Q_{Lv}= latent heat given out by vapour to form water of 100°C

Q_w= heat given by water of 100°C to come at 34°C.

putting respective values in eq. (1)

Q_T=m(L+c.\Delta T)

Q_T=25(2256+4.19\times 66)

Q_T=63313.5\ J

is the heat transferred to the skin.

4 0
4 years ago
1. A car with a mass of 2500 kg accelerates when the traffic light turns green. If the net force
soldier1979 [14.2K]

;Net force = mass of the body × acceleration of the body due to the net force

; 5000 = 2500 a...then divide both sides by 2500

; acceleration(a) = 2 m/s^2

5 0
4 years ago
A 200g air-track glider is attached to a spring. The glider is pushed in 10cm and released. A student with a stopwatch finds tha
cricket20 [7]

The spring constant will be k= 5.5N/m for a 200g air track glider attached to a spring.

<h3>What is spring constant?</h3>

The spring constant, k, is a measure of the stiffness of the spring. It is different for different springs and materials.

Calculation for What is the spring constant

First step is to calculate the time period

T = 12 second/10

T = 1.2 second

Now let calculate the spring constant using this formula

k=\dfrac{4\pi ^2m}{T^2}

Where,

m=0.2kg

T=1.2second

k represent spring constant=?

Let plug in the formula

k=\dfrac{4 \pi \times 0.2}{(1.2)^2}

k=\dfrac{39.48\times 0.2}{1.44}

k=\dfrac{7.90}{1.44}

k=5.48 N/m

k=5.5 N/m ( Approximately)

Therefore the spring constant will be 5.5 N/m

To know more about spring constant follow

brainly.com/question/1968517

#SPJ4

4 0
2 years ago
An 81.5-kg man stands on a horizontal surface.
OLga [1]

Answer:

a)V= 0.0827 m³

b)P=181.11 x 10²  N/m²

Explanation:

Given that

m = 81.5 kg

Density ,ρ = 985 kg/m³

As we know that

Mass = Volume x Density

81.5 = V x 985

V= 0.0827 m³

The force exerted by weight = m g

 F= m g= 81.5 x 10 = 815 N      ( Take ,g= 10 m/s²)

Area ,A= 4.5 x 10⁻² m²

The Pressure P

P=\dfrac{F}{A}

P = \dfrac{815}{4.5\times 10^{-2}}\ N/m^2

P=181.11 x 10²  N/m²

7 0
3 years ago
Which of the below statements are true?
andrezito [222]

Answer:

B

Explanation:

Displacement is the distance from the start point to the endpoint, displacement disregard the path taken or the amount traveled.

if you start at point A, then go to point B, and back to point A, the displacement is zero because you started and ended at the same point.

for this question, pretend you started at point A, went east 20 km to point B, and then west 8 km to point C, your displacement is 12 km. 12 km is the distance between point A and point C.

4 0
3 years ago
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