A) For upward projection.
v = u -gt
but v = 0, thus u = gt,
t = u/g, t= 7.83/9.81, t = 0.798 sec
Therefore, distance, s
S = ut -1/2gt²
= 7.83(0.798) - 1/2(9.81)(0.798²)
= 6.248 - 3.124
= 3.124 m
Total Height is 10.3 + 3.124 = 13.424 m
For the case of free fall
s= ut + 1/2 gt² but u =0
s = 1/2 gt²
t² = (2 × 13.424)/9.81
t² = 2.7368
t = 1.654 s
Therefore, the time the stone remains in air will be 1.654 + 0.798
= 2.452 seconds
b) Speed of the impact on the ground
v= u + gt but, u = 0
thus v = gt
therefore, v = 9.81 × 1.653
= 16.216 m/s
These cases are rare, but what happens is something called an occluded front. There are so many things that could be talked about and results aren't typically constant, so I recommend you look up what an occluded front is. Its basically when a cold front catches up to a warm front and forces even more warm air up, causing high amounts of precipitation.
Answer:
20 m
Explanation:
mechanical adv = distance over which the effort is applied (de) / distance the load travels (dr)
MA = de/ dr
10 = de/ 2
de = 20 m