Answer:
87.54 g of H₂O₂
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 1.55×10²⁴ molecules
Mass of H₂O₂ =.?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole of H₂O₂
Next, we shall determine the mass of 1 mole of H₂O₂. This can be obtained as follow:
1 mole of H₂O₂ = (2×1) + (2×16)
= 2 + 32
= 34 g
Thus,
6.02×10²³ molecules = 34 g of H₂O₂
Finally, we shall determine mass of H₂O₂ that contains 1.55×10²⁴ molecules. This can be obtained as follow:
6.02×10²³ molecules = 34 g of H₂O₂
Therefore,
1.55×10²⁴ molecules
= (1.55×10²⁴ × 34)/6.02×10²³
1.55×10²⁴ molecules = 87.54 g of H₂O₂
Thus, 87.54 g of H₂O₂ contains 1.55×10²⁴ molecules.
Answer:
The pOH is 4, 44 and the solution is basic.
Explanation:
The pOH is a measure of the concentration of OH (hydroxyl) ions in the solution.
The pOH is calculated as :
pOH = -log (OH-)= -log (3.67 x 10-5 )= 4, 44. In this case, the solution is basic.
The p0H scale ranges from values of 0 to 14 (less than 7.0 is basic and greater than 7.0 is acidic, a pH = 7.0 is neutral)
Answer:
200 L per day
Explanation:
If there is 1 mg of F- per L of water, we can calculate the volume for 2 g like this:
1) Converse the toxic mass of fluoride to miligrams
1 g ------- 1000 mg
0.2 g ---- X
X = 200 mg
2) Calculate the liters of fluoridated drinking water that a person can consume to reach 200 mg
1 mg -------- 1 L
200 mg ---- X
x = 200 L
Answer:
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Explanation:
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